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Right, A is the broadcast address - it is explained in better detail here: https://stackoverflow.com/questions/29034878/how-can-i-determine-network-and-broadcast-address-from-the-ip-address-and-subnet
The Answers B and C are out because their submask have the prefix /29, in A the 10.2.1.3 is the broadcast of 10.2.1.0 network. The answer correct is D because 209.165.201.2 is the 2nd available IP for 209.165.201.0 network.
Was there an instance in the actual exam wherein the choices are typographical errors? Because I chose A over D thinking that it was intentionally written as 225.
The answer is A, I saw some saying that A is a broadcast address and would like to remind everyone that broadcast addresses can be reconfigured while the mistake of having subnet mask 225.255.255.251 eliminates it as a candidate
A. interface e0/0 description to XX-AXXX:XXXXX ip address 10.2.1.3 255.255.255.252
Given address belongs to subnet 10.2.1.0/30, and it’s the broadcast address inside that subnet.
Wrong answer.
B. interface e0/0 description to XX-AXXX:XXXXX ip address 192.168.1.1 255.255.255.248
Given address belongs to subnet 192.168.1.0/29.
Wrong answer.
C. interface e0/0 description to XX-AXXX:XXXXX ip address 172.16.1.4 255.255.255.248
Given address belongs to subnet 172.16.1.0/29.
Wrong answer.
D. interface e0/0 description to XX-AXXX:XXXXX ip address 209.165.201.2 225.255.255.252
Given address belongs to subnet 209.165.201.0/30, which ranges from 209.165.201.1 to 209.165.201.2.
Correct answer.
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