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Exam CWNA-107 topic 1 question 57 discussion

Actual exam question from CWNP's CWNA-107
Question #: 57
Topic #: 1
[All CWNA-107 Questions]

You are troubleshooting a client problem with a 2.4 GHz WLAN connection. The client is experiencing surprisingly low data rates during the work day. You analyze the workspace outside of business hours and detect a strong signal with a typical noise floor at the client location. During working hours, the user works with a laptop in the area and uses an external USB hard drive for continuous data access. The user also states that the laptop works as expected on her home network.
The user working approximately 8 feet away from this client experiences no problems.
Based on this information, what is the likely cause of the problem?

  • A. The laptop has a failing wireless adapter
  • B. The AP is overloaded during the work day
  • C. The external hard drive is USB 3.0 and is causing a significant increase in the noise floor when in use
  • D. The drives in the laptop are corrupt
Show Suggested Answer Hide Answer
Suggested Answer: B 🗳️

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VPP
Highly Voted 3 years, 10 months ago
correct answer is C. USB 3.0 may be causing interference with 2.4GHz
upvoted 8 times
CWNA
3 years, 3 months ago
USB never make RF noise! answer is B
upvoted 1 times
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EAG
Most Recent 2 years, 11 months ago
Answer is C. USB 3.0 can cause interference as Cade47 stated and referenced. In addition, reading the question carefully, we can eliminate options A and D, since the laptop works as expected at the user's home (unlike at office location) Option B can also be eliminated because another user 8 feet away, who will most likely be connected to the same AP is having no issues, thus the AP cannot be the problem in any way. This leaves option C.
upvoted 2 times
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Cade47
3 years, 3 months ago
I think the key to this topic is in the question "user 8' feet away work fine" I believe the answer to be C. Reference pg268 CWNA107 study guide states USB 3.0 can generate significant interference in the 2.4Ghz band
upvoted 4 times
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A (35%)
C (25%)
B (20%)
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