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Exam ICBB topic 1 question 109 discussion

Actual exam question from Six Sigma's ICBB

Question #: 109
Topic #: 1

[All ICBB Questions]

Using this partial Z Table, how many units from a months production run are expected to not satisfy customer requirements for the following process?
Upper specification limit: 7.2 Lower specification limit: 4.3 Mean of the process: 5.9 Standard Deviation: 0.65 Monthly production: 450 units

A. 3
B. 7
C. 10
D. 12

Show Suggested Answer

Suggested Answer: C 🗳️

by QRMAK at July 25, 2020, 7:27 p.m.

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VazBelt

2 years, 8 months ago

I think this question doesn't have the right answer option of 13 as available on another forum. The correct answer should be 13. * Find Z score @ UCL and @ LCL. viz Area left of UCL = 0.97725 and Area left of LCL = 0.00695 * Subtracting the two will give the area under the curve. 0.9703 * 1 minus the above area will give the failure zone. i.e. 0.0297 * multiply with the N i.e. 450 X 0.0297 = 13.36 > This is no. of units NOT to satisfy customer requirement.

upvoted 3 times

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turbosiput

2 years, 10 months ago

Apply Z score formula. Z=(UCL-mean)/SD => Z=2. From there found P(Z)=0.97725. Need to find outside of normal curve= 1-P = 0.02275. Multiply 0.02275 with 450 you get 10.2375. Hence the answer is 10.

upvoted 2 times

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Prnysingh

3 years, 8 months ago

Me too.. pls help out anyone

upvoted 1 times

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QRMAK

3 years, 9 months ago

I need full solution plz