Suggested Answer:A🗳️
An IPv4 address in dotted decimal format is constructed using binary arithmetic. In binary arithmetic, each bit within a group represents a power of two. Specifically, the first bit in a group represents 2 to the power of 0, the second bit represents 2 to the power of 1, the third bit represents 2 to the power of 2, and so on. Binary format is simple because each successive bit in a group is exactly twice the value of the previous bit. The first octet is 128 + 32 + 8 + 4 = 172 The second octet 64 + 32 + 16 + 8 + 2 + 1 = 123
The third octet 8 + 4 + 1 = 13 - The fourth octet is 128 + 16 + 8 + 4 + 1 = 157 Reference: https://en.wikipedia.org/wiki/IPv4
Meh
Let's do some eliminations
The 4th value is 10011101, that starts with 1 then 00, so it is something greater that 128 (but not much) : this rules out answers C (15 < 128) and B (57 < 128)
The second value, 01111011, starts with 0 then 1, so less than 128, but more than 64
This rules out answer B : 13 < 64
So, the answer is A: 172.123.13.157
A - by checking the first bit, 0 -> even number, 1 -> odd number. So odd-even-even-even -> A
upvoted 2 times
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Community vote distribution
A (35%)
C (25%)
B (20%)
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