Exam 156-587 topic 1 question 76 discussion

The correct answer is: A. fw ctl kdebug -T -f -m 10 -s 1000000 -o debugfilename To run a kernel debug over a longer period of time while ensuring that the output does not fill up the disk space, the following options are used: ・-T: Adds a timestamp to the debug output. ・-f: Runs the debug in the foreground. ・-m 10: Limits the maximum size of the debug file to 10 GB (in this case, 10 GB is specified as the free space available). ・-s 1000000: Specifies the maximum number of lines to store in the debug file. ・-o debugfilename: Writes the debug output to the specified file (debugfilename). C. fw ctl kdebug -T -f -m 10 -s 1000000 > debugfilename: This syntax uses > for redirection, which may not properly handle file rotation and size limitations.

C is wrong, you can check in the lab, would give you below [Expert@R82:0]# fw ctl kdebug -T -f -m 10 -s 1000000 > debugfilename -m option requires -o Usage: fw ctl kdebug [-f] [-o <file>] [-b <buffer size>] [-k] [-v ("<vs ids>"|all)] [-t|-T] [-p fld1[,fld2..] [-m num [-s size]] -t/-T to print the time field (seconds/microseconds) -p to print specific fields all|proc|pid|mid|type|freq|time|ticks|tid|text|errno|host|vsid|cpu -m - number of cyclic files, -s - size of each

there is no flag for output file as was also shown in other questions in this exam. in kdebug the output is directly into a text file using >