Exam 200-301 topic 1 question 884 discussion

You should be able to just eyeball this. Hex isn't hard, but if we break down each MAC address, converting each octet into decimal: A. MDF-DC-1: 08:E0:43:42:70:13 -> [8, 224, 67, 66, 112, 19] B. MDF-DC-2: 08:0E:18:22:05:97 -> [8, 14, 24, 34, 5, 151] C. MDF-DC-4: 08:E0:19:A1:B3:19 -> [8, 224, 25, 161, 179, 25] D. MDF-DC-3: 08:0E:18:1A:3C:9D -> [8, 14, 24, 26, 60, 157] We see that D is the lowest. In STP, if all priorities are the same, then the lowest MAC address wins. D is the answer.

If you don't know the answer to this question by now, I would suggest to start all over at page 1.

If you didn't pick D, you need to look over the basics

B is correct Be careful, it took me a while to see that some start with 0E and others with E0

D is correct

B for sure

why people selected D?

idk how you guys are getting thoose crazy numbers... A1 is 10+1 and 22 is 22 meaning D is lower than B

defintly D

I don't understand if i'm calculating right the hexadecimals, if someone could give me a light i would appreciate: A 08:E0:43:42:70:13 = 496 08 = 0000 1000 = 8 E0 = 1111 0000 = 240 43 = 0100 0011 = 67 42 = 0100 0010 = 66 70 = 0110 0000 = 96 13 = 0001 0011 = 19 B 08:0E:18:22:05:97 = 237 08 = 0000 1000 = 8 0E =0000 1111 = 15 18 = 0001 1000 = 24 22 = 0010 0010 = 34 05 = 0000 0101 = 5 97 = 1001 0111 = 151 C 08:E0:19:A1:B3:19 = 638 08 = 0000 1000 = 8 E0 = 1111 000 = 240 19 = 0001 1001 = 25 A1 = 1010 0001 = 161 B3 = 1011 0011 = 179 19 = 0001 1001 = 25 D 08:0E:18:1A:3C:9D = 290 08 = 0000 1000 = 8 0E = 0000 1111 = 15 18 = 0001 1000 = 24 1A = 0001 1010 = 26 3C = 0011 1100 = 60 9D = 1001 1101 = 157 and according to my calculations, B would be the answer if it is the lowest MAC address

D. MDF-DC-3: 08:0E:18:1A:3C:9D

Given answer is right.

08:E0:43:42:70:13 - 400 08:0E:18:22:05:97 - 164 08:E0:19:A1:B3:19 - 610 08:0E:18:1A:3C:9D - 283 Am I wrong ? And if I am not - how it is possible "D" to be the correct answer ?!

Correct : The default value is 32768, and the lowest number is preferred. In the case of a tie, the switch with the lowest MAC address will be selected.