A router has four interfaces addressed as 10.1.1.1/24, 10.1.2.1/24, 10.1.3.1/24, and 10.1.4.1/24. What is the smallest summary route that can be advertised covering these four subnets?
d) 10.1. equal all, no
a) e b) /22 ==> 128/64/32/16/8/4 (=22) - network is 0, 4, 8 ..., no
c) /21 ==> 128/64/32/16/8 (=21) - is 0, 8, 16 = correct
This embrace the 4 range
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