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Exam 300-410 topic 1 question 573 discussion

Actual exam question from Cisco's 300-410
Question #: 573
Topic #: 1
[All 300-410 Questions]









Refer to the exhibit. An engineer troubleshoots a connectivity problem that is impacting the communication from the users at segment 172.16.3.16 /28 to the server farm at 192.168.5.16/
28. Which configuration resolves the issue on router R1?

  • A. router rip
    redistribute ospf 1 metric 16
  • B. router ospf 1
    redistribute rip metric 14
  • C. router rip
    redistribute ospf 1 metric 14
  • D. router ospf 1
    redistribute rip metric 16
Show Suggested Answer Hide Answer
Suggested Answer: C 🗳️

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dapardo
Highly Voted 11 months ago
Selected Answer: C
After investigating a little bit more Im going with C. I have found this article that actually agrees with Pietjeplukgeluk. Any value greater than 15 will be considered infinite. https://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing-protocol-eigrp/8606-redist.html
upvoted 5 times
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Pietjeplukgeluk
Highly Voted 11 months, 3 weeks ago
Selected Answer: C
C seems correct as 16 will be "unreachable", we should reduce hop count to allow adjacent router to keep hop-count below 16==unreachable
upvoted 5 times
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bk989
Most Recent 9 months ago
The exhibit shows R2: router rip redistribute ospf 1 metric 15 On R3 we see the R1 connected link 192.168.250.0 [120/15] So we need to reduce the metric to 14, by the time it reaches R3 the metric will be 15. Mac metric rip = 16. R3 is getting the R1 connected link through R2 redsitribution, presumably theres a ,link problem between R3 and R1. Answer = C.
upvoted 3 times
bk989
8 months, 2 weeks ago
update: There is no like problem between R3 and R1. R2 did redistribution first, that's why there's no route. Answer = C. Redistribute metric 14, it stays as metric 14 when arriving on R3 (I labbed it) and it gets metric 15 when arriving on R4.
upvoted 1 times
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bk989
8 months, 3 weeks ago
The metric on R3 = 15. When R2 and R1 redistributed with metric 15, the metric stayed as 15 when going to R3. It was 16 when arrived at R4. Max metric is 16. Therefore R4 has no ip route, and traceroute fails. When redistributing with metric 14, the route gets advertised as metric 14 to R3. Advertised as 15 to R4. We see one route to the 192.168.56.16 network on R3, the route points to the neighbor that did the ospf to rip redistribution first.
upvoted 2 times
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bk989
9 months ago
Max metric rip = 16.
upvoted 2 times
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[Removed]
9 months, 2 weeks ago
Selected Answer: C
C is corerct
upvoted 2 times
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Ivan_AGC
10 months, 2 weeks ago
Selected Answer: A
If you see the metric in R3 it is [110/15], in R4 you do not get the route, in my opinion, C is wrong because if the metric is configured in 15 reducing it to 14 will not help to deliver the route.
upvoted 1 times
bk989
8 months, 1 week ago
we are redistributing with metric 15 currently. On next hop router it is metric 15 on R3. On R4 it gets metric 16 and poisoned out - max metric = 16. So we need to redistribute metric 14, it reaches ER3 with metric 14. The reason why the metric didn't increase from R1 to R3 is because R1 is advertising the route, it didn't originate the route.
upvoted 1 times
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chaba7654321
1 year ago
Selected Answer: A
A works for me in a lab
upvoted 3 times
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Keegom
1 year ago
Selected Answer: C
My choice is C: "RIP uses the hop count as a routing metric. RIP prevents routing loops by implementing a limit on the number of hops allowed in a path from the source to a destination. The maximum number of hops allowed for RIP is 15. This hop limit, however, also limits the size of networks that RIP can support." https://community.cisco.com/t5/networking-knowledge-base/ripv2-routing-information-protocol/ta-p/3117425
upvoted 4 times
dapardo
11 months, 3 weeks ago
wrong: R2(config)#router rip R2(config-router)#redi R2(config-router)#redistribute os R2(config-router)#redistribute ospf 1 me R2(config-router)#redistribute ospf 1 metric ? <0-16> Default metric transparent Transparently redistribute metric R2(config-router)#redistribute ospf 1 metric
upvoted 1 times
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Selected Answer: A
I would pick "A" because of poison reverse.
upvoted 3 times
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