NONE of the options are fully correct — but if option A had used 10.2.1.1 or 10.2.1.2 instead of .3, it would be right and if Option D had used a correct subnet mask (255.255.255.252), it would be correct too.
A. interface e0/0 description to XX-AXXX:XXXXX ip address 10.2.1.3 255.255.255.252
Given address belongs to subnet 10.2.1.0/30, and it’s the broadcast address inside that subnet.
Wrong answer.
B. interface e0/0 description to XX-AXXX:XXXXX ip address 192.168.1.1 255.255.255.248
Given address belongs to subnet 192.168.1.0/29.
Wrong answer.
C. interface e0/0 description to XX-AXXX:XXXXX ip address 172.16.1.4 255.255.255.248
Given address belongs to subnet 172.16.1.0/29.
Wrong answer.
D. interface e0/0 description to XX-AXXX:XXXXX ip address 209.165.201.2 225.255.255.252
Given address belongs to subnet 209.165.201.0/30, which ranges from 209.165.201.1 to 209.165.201.2.
Correct answer.
The answer is A. Yes it it a board cast address but it’s also a point to point link, which doesn’t need to utilize the broadcast IP. So we can assign it to a device instead. Plus the scenario doesn’t mention using public IP addresses go a routers to communicate. It’s could be a vpn connection for all we know.
The Answers B and C are out because their submask have the prefix /29, in A the 10.2.1.3 is the broadcast of 10.2.1.0 network. The answer correct is D because 209.165.201.2 is the 2nd available IP for 209.165.201.0 network.
The answer is A, I saw some saying that A is a broadcast address and would like to remind everyone that broadcast addresses can be reconfigured while the mistake of having subnet mask 225.255.255.251 eliminates it as a candidate
lol, yeah they can be reconfig, same as an IP host and gateway, but the question is not asking what the hell you can do, is only telling you, determine mask 30, and find a range of IPs available.
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