Refer to the exhibit. Users in the branch network of 2001:db8:0:4::/64 report that they cannot access the Internet. Which command is issued in IPv6 router EIGRP 100 configuration mode to solve this issue?
By observing the routing table we can determine that: 1) the default static route isn't learned on the branch router 2) R1 networks were learned. This concludes that on R1 we have eigrp stub connected which advertises only connected networks to Branch router.
B is correct. Stub routing in EIGRP means the router only shares some of its routes with neighbors like connected routes, summary routes, static routes, and redistributed routes. by default, when a router is configured as an EIGRP stub, it advertises connected and summary routes.
If you look closely you see that R1 learns the default route::/0 from R2 via Gig0/1 but is not advertising it to the Branch router
Stub announces by default the connected and summary routes.
Refer to the diagram and the exhibit. All interfaces are participating in the routing processes shown in the diagram, and all neighborships have been formed. In addition, all the necessary routes have been exchanged. Which statement is correct in relationship to redistribution?
answers are :
BGP AS 65500 will not learn any EIGRP AS 100 prefixes.
Branch will learn all IPv4 prefixes except 192.0.2.1.
R2 will not learn any prefixes in EIGRP AS 100.
Branch will learn all IPv4 prefixes in the diagram.
Correct answer is B. In Router 1's RIB we can see the default route, which is advertised as an EIGRP Route. By-default Router can't advertised routes, which he leant vie EIGRP, when there is Stub configuration. So R1 can advertise gig1/0 link subnet, but not default route because of restriction.
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