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Exam 200-301 topic 1 question 368 discussion

Actual exam question from Cisco's 200-301
Question #: 368
Topic #: 1
[All 200-301 Questions]


Refer to the exhibit. If OSPF is running on this network, how does Router2 handle traffic from Site B to 10.10.13.128/25 at Site A?

  • A. It sends packets out of interface Fa0/1 only.
  • B. It sends packets out of interface Fa0/2 only.
  • C. It load-balances traffic out of Fa0/1 and Fa0/2.
  • D. It cannot send packets to 10.10.13.128/25.
Show Suggested Answer Hide Answer
Suggested Answer: D 🗳️
by Texter at Jan. 25, 2021, 6:43 p.m.

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admin1982
Highly Voted 4 years, 3 months ago
@ Texter: Router 2 does not have an entry for the subnet 10.10.13.128/25. It only has an entry for 10.10.13.0/25, which ranges from 10.10.13.0 to 10.10.13.127. You're welcome - Je vous en prie
upvoted 32 times
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mrsiafu
Highly Voted 4 years, 1 month ago
Usuable range 10.10.13.1 to 10.10.13.126 for this /25
upvoted 15 times
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[Removed]
Most Recent 1 year, 2 months ago
Selected Answer: D
D is correct
upvoted 2 times
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xplinty666
1 year, 2 months ago
Pregunta trampa
upvoted 1 times
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[Removed]
1 year, 5 months ago
Selected Answer: D
Why do they have to play these games with us!? Waste my time thinking about OSPF and it's just a subnetting question.
upvoted 8 times
MicroDiff
9 months, 2 weeks ago
cisco and your jokes
upvoted 1 times
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jeremykebir
1 year, 5 months ago
AHAAH they are the best for this kind of question Guys be focus!!
upvoted 3 times
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Msandie
1 year, 10 months ago
I didnt think about subnetting at all
upvoted 4 times
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ZUMY
2 years, 8 months ago
D is okay
upvoted 1 times
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[Removed]
2 years, 9 months ago
What a ridiculus question; Shame on cisco;
upvoted 8 times
DoBronx
2 years, 7 months ago
always subnet
upvoted 2 times
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MK_Engr
2 years, 11 months ago
It was Subnet mask related question, NOT routing related, lol
upvoted 6 times
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tweesgger
3 years, 7 months ago
10.10.13.0/25 subnet does not include 10.10.13.128 because it is the subnet network address of the next subnet block for the /25 prefix, since it is not even a usable address to begin with, such scenario can only be hypothetical and no such situation can be found in an up and working network.
upvoted 2 times
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CISCO2022
3 years, 12 months ago
X.X.X.0 /25 = Bit 25 is 128 increment = first net ID .0 Broadcast 127 IPs 0-126 2nd Net ID 128 Broadcast 255 IPs 129-254 10.10.13.128 is a Network ID
upvoted 6 times
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Texter
4 years, 3 months ago
Could someone help explain how the IP Address range(s) are generated. Thank you - Merci beacoup.
upvoted 2 times
kyleptt
1 year, 11 months ago
essentially .128 is none useable IP address
upvoted 1 times
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C (25%)
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