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Exam 300-135 All Questions

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Exam 300-135 topic 7 question 54 discussion

Actual exam question from Cisco's 300-135
Question #: 54
Topic #: 7
[All 300-135 Questions]

Refer to the exhibit. PC-2 failed to establish a Telnet connection to the Terminal Server. Which solution allows PC-2 to establish the Telnet connection?

  • A. Gateway-Router(config)#ipv6 access-list Default_Access Gateway-Router(config-ipv6-acl)#no sequence 20 Gateway-Router(config-ipv6-acl)#sequence 5 permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet
  • B. Gateway-Router(config)#ipv6 access-list Default_Access Gateway-Router(config-ipv6-acl)#permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet
  • C. Gateway-Router(config)#ipv6 access-list Default_Access Gateway-Router(config-ipv6-acl)#sequence 15 permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet
  • D. Gateway-Router(config)#ipv6 access-list Default_Access Gateway-Router(config-ipv6-acl)#sequence 25 permit tcp host 2018:DB1:A:B::2 host 2018:DB1:A:C::1 eq telnet
Show Suggested Answer Hide Answer
Suggested Answer: A 🗳️

Comments

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tio1
Highly Voted 5 years, 6 months ago
C is correct, option with no sequence will just be added with a higher sequence, so will not correct the issue
upvoted 5 times
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MIi2604
Highly Voted 5 years, 7 months ago
C is correct
upvoted 5 times
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KZM
Most Recent 11 months, 3 weeks ago
Selected Answer: C
The rule with sequence 20 that denies Telnet traffic from any host to the Terminal Server, while permitting traffic from PC-2 to the Terminal Server, is not effective. Therefore, creating a new permit rule with a lower sequence number than 20 would be the best solution.
upvoted 1 times
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rob899
1 year, 7 months ago
Selected Answer: A
A is the correct answer. sequence 10 permits PC-1 to reach the server on "www" sequence 20 denies all Telnet to server: deny tcp "any" to "host 2018:DB1:A:C::1 eq telnet"), sequence 30 is blocked by sequence 20 so this rule will never be hit: "permit host 2018:DB1:A:B::2" to host "host 2018:DB1:A:C::1 eq telnet" the answer is to add a rule before sequence 20 that allows telnet to the server. sequence 30 is a good rule but it is in the wrong place, being covered by sequence 20.
upvoted 2 times
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asans
3 years ago
Correct answer is A. When you input an ACE entry that matches what's already there, it will not add. Proved it by labbing. Also from cisco under section - Sequence Numbering Behavior: "If you enter an entry that matches an already existing entry (except for the sequence number), then no changes are made." Link:https://www.cisco.com/en/US/docs/ios-xml/ios/sec_data_acl/configuration/15-2mt/sec-acl-seq-num.html#GUID-15B01A19-C401-4C70-84AA-5DF6C8EF133C
upvoted 1 times
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Spyrous
3 years, 1 month ago
Just tested it with ipv4 and ipv6 access-list. When you apply the exact same entry with a different sequence, nothing changes. The access-list keeps only the old entry. So answers B,C,D are wrong since they make no difference. Answer A is correct since despite the fact that it adds the same entry as the other answers (and changes nothing) it removes the telnet-deny-entry ( no sequence 20), hence telnet is permitted.
upvoted 3 times
Spyrous
3 years, 1 month ago
Please check IP Access List Entry Sequence Numbering: https://www.cisco.com/en/US/docs/ios-xml/ios/sec_data_acl/configuration/15-2mt/sec-acl-seq-num.html
upvoted 3 times
wts
3 years, 1 month ago
Oh yeah "If you enter an entry that matches an already existing entry (except for the sequence number), then no changes are made."
upvoted 1 times
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wts
3 years, 2 months ago
Selected Answer: A
A lot of extra text printed in a bunch. But in general, everything is simple. It is necessary to remove the 20th line or allow telnet from the server before it.
upvoted 1 times
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gndrx78
3 years, 4 months ago
A and C both seem to work but with A we have a duplicate ACE. Moreover C is the fastest. I go for C
upvoted 3 times
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RexChen
3 years, 4 months ago
Router(config-ipv6-acl)#no sequence ? <1-4294967294> Sequence number for this entry there is no seq command But why remove seq 20 ,just add to seq 15 , So C
upvoted 4 times
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chaospikes
5 years, 2 months ago
Sorry but I have to disagree. An IPv6 access-list does have the "no sequence #" option available. What does not work is trying to re-sequence a line without first removing it with the "no" command. Therefore A is the only viable answer here as it legally removes the deny statement blocking telnet. The second command to re-sequence sequence 30 will be accepted by the router but will have no effect. I have tested this all just now on a live ASR.
upvoted 2 times
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Joe812
5 years, 3 months ago
no sequence shouldn't be a valid command so A won't work...I think it is no # or no... no <1–2147483647> no <permit|deny> <ipv6–ACE–criteria>
upvoted 2 times
Mknighttime
5 years, 3 months ago
no sequence # does work so I can be a valid answer, but in this exam I think they want you to do the minimal amount of changes to make it work
upvoted 1 times
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Sk123456789
5 years, 3 months ago
C is most likely answer although A would work as well. There's no need to remove sequence 20 if a permit statement is added before it though which C does.
upvoted 3 times
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th0rstenb0
5 years, 3 months ago
only possible answer is A, please read correctly
upvoted 1 times
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pen08
5 years, 4 months ago
sequence 10 - will deny any telnet to the terminal.
upvoted 1 times
Penn
5 years, 4 months ago
seq 20 A
upvoted 1 times
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Fiss
5 years, 6 months ago
C is Correct Answer
upvoted 4 times
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