Exam 350-501 topic 1 question 159 discussion

I think C is correct: ip pim spt-threshold {kbps| infinity}[group-list access-list] Specifying the infinity keyword causes the router never to move to the shortest-path tree; it remains on the shared tree. This keyword applies to a multicast environment of "many-to-many" communication. https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/ipmulti_optim/configuration/12-4t/imc-optim-12-4t-book/imc_pim_sparse.html

Network administrators can force traffic to stay on the shared tree by using the Cisco IOS ip pim spt-threshold infinity command.

C is correc

I agree with you. C should be the right answer

Like the others pointed out C is correct, Search the doc for infinity. https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/mcst_ovr.html

IOS command: ip pim spt-threshold {kbps| infinity}[group-list acl-name] IOS XR command: spt-threshold infinity [group-list acl-name] The infinity keyword will cause all the sources for the specified group to never switch over to an SPT and continue using the shared tree. Answer C

Yes I agree with C. "If the shared tree is not an optimal path between the source and the receiver, the routers dynamically create a source tree and stop traffic from flowing down the shared tree. This behavior is the default behavior in software. Network administrators can force traffic to stay on the shared tree by using the ip pim spt-threshold infinity command." https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/ipmulti_pim/configuration/xe-16/imc-pim-xe-16-book/imc-tech-oview.html