Exam 200-301 topic 1 question 351 discussion

Here's a short subnet chart. You can write down a chart before the test starts /32 - 1 /31 - 2 /30 - 4 /29 - 8 /28 - 16 /27 - 32 /26 - 64 /25 - 128 /24 - 256 /23 - 514 Check the routing table and look for a subnet that fits the 10.10.13.165 IP address. the only one that fits is 10.10.13.160/29. As you can see in this chart, /29 is equal to 8 total addresses and 6 total hosts (You have to subtract 2 from the total number of addresses to get the amount of hosts). 10.10.13.160 +6 = 166 which is the last usable address for 10.10.13.160/29. You pretty much do the same thing to find the router it'll send it out of.

Router 3 is the correct answer. Hard question. Need to be well versed on subnetting. The subnet on the routing table that has 10.10.13.165 is the 10.10.13.160/29. The 10.10.13.160/29 subnet is routed via 10.10.10.5 which is one of the usable hosts on the subnet between R1 and R3. So the host 10.10.13.165 is reachable via R3.

B is correct

B is correct, refer to the explenations by TheLorenz and DatBroNZ

/28 = 248 and increment is 16 /29 = 240 and increment is 8 Destined host IP = 10.10.13.165 160 network host range for /28 is 160-175. Usable IP 161-174 160 network host range for /29 is 160-167. Usable IP 161-166 So we go with /29 O 10.10.13.160/29 [110/2] via 1010.10.5 Router 3 network is 10.10.10.4/30 increment is 4 Usable IP for 10.10.10.4/30 network is 5 and 6 Router 3 WAN IP are 10.10.10.5 and 10.10.10.6

I'ts B

1. Which route, inside the routing table, includes address 10.10.13.165? It’s the route to subnet 10.10.13.160/29. This subnet has the following characteristics: /29 means 3 bits in the host ID -> 2^3 – 2 = 6 IP addresses. 1st IP address = 10.10.13.161 Last IP address 10.10.13.166 2. Which is the exit interface for this route? It’s Ge0/1, which leads to IP 10.10.10.5 (the next-hop for this route). 3. Which subnet, among those shown in the exhibit, includes the next-hop’s IP address? It’s subnet 10.10.10.4/30. Again: /30 means 2 bits in the host ID -> 2^2 – 2 = 2 IP addresses. 1st IP address = 10.10.10.5 Last IP address 10.10.10.6 The next-hop is inside this subnet and it’s Router 3. The remaining IP address, 10.10.10.6, is Router 1’s Ge0/1 IP address. A. Router2 Wrong answer. B. Router3 Correct answer. C. Router4 Wrong answer. D. Router5 Wrong answer.

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First we need to check routing table to find out which network 10.10.13.165 IP address belongs to. If we check routing table, 10.10.13.160/29 IP address/Mask combination covers the following IP addresses: 10.10.13.160 (network address), 10.10.13.161, 10.10.13.162, 10.10.13.163, 10.10.13.164, 10.10.13.165, 10.10.13.166, 10.10.13.167 (Broadcast address). Since the address to go is 10.10.13.165, the network it is in is 10.10.13.160/29. But, In order to go 10.10.13.160/29 network, we need to pass from 10.10.10.5 next hop address. The question asks us which router has that address. In order to find it, we need to look at question. We see many 10.10.10.X/30 networks. If we analyse 10.10.10.4/30, we see that it covers 10.10.10.4 (network address), 10.10.10.5, 10.10.10.6 and 10.10.10.7(broadcast address) addresses. So 10.10.10.5 address belongs to 10.10.10.4/30 network which is netween router1 and router3. So the answer is Router3.

idk why it says r3 , I think its r4

can someone explain this to me please,i am lost

can any one explain it tome please ?