Exam 300-415 topic 1 question 166 discussion

Answer should be 5, can anyone confirm?

D is the correct answer - See the documentation Number of Paths Advertised per Prefix Specify the maximum number of equal-cost routes to advertise per prefix. vEdge routers advertise routes to vSmart controllers, and the controllers redistribute the learned routes, advertising each route-TLOC tuple. A vEdge router can have up to four TLOCs, and by default advertises each route-TLOC tuple to the vSmart controller. If a local site has two vEdge routers, a vSmart controller could potentially learn eight route-TLOC tuples for the same route. If the configured limit is lower than the number of route-TLOC tuples, the best route or routes are advertised. Range: 1 through 16 Default: 4 https://sdwan-docs.cisco.com/Product_Documentation/vManage_Help/Release_18.3/Configuration/Templates/OMP

Since 20.5, the range has been 1-16, default 4. Correct answer is 1, but not listed. I think Cisco is looking for 5, because it's the next step up from default if you wanted to increase the value

C is correct The "number of paths" setting is per DEVICE

5 per device

The Answer is C Only 4 Paths can be advertised per prefix in the Overlay Management Protocol. The customer alludes to having 3 ISP circuits and 2 Private. The singular prefix would require at least 5 (4 by default, 1 advertisement to the Private Networks)

I think the given answer is good because if they said that the remote site have 2 vedges and they has 5 links, so as minimum 1 prefix/vedge and there are 2 vedges 2x5 = 10

Should be C because by default it is 4.