Exam 200-901 topic 1 question 32 discussion

Actual exam question from Cisco's 200-901

Question #: 32
Topic #: 1

Refer to the exhibit.

The JSON data in the exhibit has been parsed and stored into a variable `data`. What returns the value `172.16.0.11`?

A. data['items']['host']['value']
B. data['items'][1]['host']['value']
C. data['items'][0]['host']['value']
D. data['items']['host'][1]

Show Suggested Answer

Suggested Answer: C 🗳️

by bitstomp at March 1, 2022, 9:16 a.m.

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macxsz

Highly Voted 6 months ago

Selected Answer: C

Only C As only C has [0] which is the first element of the list

upvoted 6 times

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kibo_muc

Most Recent 7 months ago

Selected Answer: C

C is correct - I was confused at first.. But i think: ITEMS - is a dictionary with a list as its value. This list has only one entry though - hence you need the positional arg 0 to target the nested K/V pairs.

upvoted 4 times

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anonymous1966

8 months ago

without special chars: The JSON data in the exhibit has been parsed and stored in a variable, "data". What returns the value "172.16.0.11" ? A. data['items']['host'][1] B. data['items'][O]['host']['value'] C. data['items']['host']['value'] D. data['items']['1']['host']['value']

upvoted 2 times

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bitstomp

9 months, 1 week ago

C - print(data["items"][0]["host"]["value"])

upvoted 3 times

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