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Exam 200-301 topic 1 question 435 discussion

Actual exam question from Cisco's 200-301
Question #: 435
Topic #: 1
[All 200-301 Questions]


Refer to the exhibit. Which two prefixes are included in this routing table entry? (Choose two.)

  • A. 192.168.1.17
  • B. 192.168.1.61
  • C. 192.168.1.64
  • D. 192.168.1.127
  • E. 192.168.1.254
Show Suggested Answer Hide Answer
Suggested Answer: AB 🗳️
by MCMH2000 at May 10, 2022, 3:22 p.m.

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netzwork
Highly Voted 2 years, 10 months ago
If Cisco is wording questions like this, they should take a dive off a cliff
upvoted 31 times
bikila123
2 years ago
😀hhhhh
upvoted 1 times
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MCMH2000
Highly Voted 3 years, 3 months ago
Question should be: "Which two IP addresses are included in this routing table entry?"
upvoted 10 times
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smokeylethal
Most Recent 1 month, 3 weeks ago
Selected Answer: AB
Yo wtf is up with the way they be framing the questions.. might as well start a cisco grammar course.
upvoted 1 times
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MinSun600
1 year ago
AE correct too
upvoted 2 times
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TmNvrWts
1 year, 1 month ago
Selected Answer: AB
Given is correct. Thanks for the grammar lecture cisco. Nobody calls it prefixes, but let's stick to the really important things. Networking is secondary -_-
upvoted 2 times
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bikila123
2 years ago
C is network address D and E are broadcast address for a given network
upvoted 5 times
bikila123
2 years ago
A and B are correct answer
upvoted 1 times
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PaddyInNZ
1 year, 8 months ago
Well, option 'd' is certainly a broadcast address. However, option 'e' cannot be a broadcast address. Broadcast address always end with an odd number (E.g.: 127, 255, etc.) In this case, 192.168.1.254 is the last usable host address in the range. 😊.
upvoted 2 times
MinSun600
1 year ago
that's what i was see it too Thank you for explanation and should be called hosts not prefixes on this case the choice should be 3 not Two
upvoted 2 times
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splashy
2 years, 11 months ago
Question is written by a edonkey, "prefixes" should be "hosts"
upvoted 6 times
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DARKK
3 years, 2 months ago
Selected Answer: AB
192.168.0-63 because /26 = 64 IP addresses per subnet and 4 subnets (256/64), 0-63, 64-127, 128-191, 192-255. A & B are correct.
upvoted 4 times
moses23
2 years, 6 months ago
How does this correlate with the answers?
upvoted 2 times
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Community vote distribution
A (35%)
C (25%)
B (20%)
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