Exam 350-401 topic 1 question 416 discussion

Actual exam question from Cisco's 350-401

Question #: 416
Topic #: 1

DRAG DROP -
An engineer plans to use Python to convert text files that contain device information to JSON Drag and drop the code snippets from the bottom onto the blanks in the code to construct the request. Not all options are used.
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by uzbin at Sept. 12, 2022, 1:49 p.m.

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uzbin

Highly Voted 2 years, 10 months ago

File 'raw-data.tx' is referenced by the variable input_file, so first text box should contain - with open(input_file) as text: Rest looks correct.

upvoted 37 times

nhawley

2 years, 8 months ago

Agreed, you should reference the variable input_file

upvoted 1 times

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Caradum

2 years, 7 months ago

uzbin is right.

upvoted 1 times

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Makaveli1

2 years, 6 months ago

No, the variable "input_file" will contain text string 'raw-data.txt', not the file. To open the file you use the context manager. >>> input_file = 'raw-data.txt' >>> input_file 'raw-data.txt' The given answer is correct.

upvoted 2 times

danman32

1 year, 11 months ago

the function open() requires text as input option, whether that is literal or through a variable containing text that specifies the file name. The given answer specifies an undefined variable.

upvoted 2 times

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nushadu

2 years, 6 months ago

you are wrong; with open('some_file.txt', 'w') as f: f.write('hello') <<<<<<<<<<<< write text into the file with open('some_file.txt') as f: print(f.read()) <<<<<<<<<<<<<<<<< read hello <<<<<<<<<<<<<<< output my_file = 'some_file.txt' <<<<<<<<<<<<< just variable with open(my_file) as f: <<<<<<<<<<<<< use it in the code print(f.read()) hello

upvoted 2 times

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HarwinderSekhon

2 years, 1 month ago

Tested -- myfilename = 'dummy.txt' # open the file for reading (replace 'file.txt' with your file name) with open(myfilename, 'r') as file: # read the content of the file data = file.read() # print the content print(data)

upvoted 2 times

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AbdullahMohammad251

Most Recent 9 months, 1 week ago

The open () method in Python expects a file path in double quotes as a parameter. without quotes, you would get an error: "NameError: name 'raw-data' is not defined." The correct answer is: with open(input_file) as text: out_file = open("Json-Output.json", "w") out_file.close()

upvoted 3 times

AbdullahMohammad251

9 months, 1 week ago

https://stackoverflow.com/questions/62347631/why-is-it-possible-to-pass-a-file-as-a-string-to-the-open-function https://www.freecodecamp.org/news/with-open-in-python-with-statement-syntax-example/

upvoted 1 times

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