10.0.12.1 is the IP configured on the router interface Gi0/1, whereas the next hop address is 10.0.12.2 and the route to get to subnet 192.168.0.55 is hanging off the neighbouring router. So, to get that 192.168.0.55 subnet, R1 will send traffic out of its Gi01 interface pointing to 10.0.12.2 next hop neighbouring router's interface which will pass it on to the subnet 192.168.0.55 hanging off its LAN interface. The routing table shows you 192.168.0.0/24 via 10.0.12.2 route, which clearly means the next hop address of the neighbouring router and 192.168.0.55 falls in that range of addresses. Hope this clarifies it :)
192.168.0.0/24
Network Address - 192.168.0.0
Broadcast Address - 192.168.0.255
First Usable- 192.168.0.1
Last Usable - 192.168.0.254
That is why 192.168.0.55 which is the C option is correct.
Here, as far as i understand the longest prefix matches the 192.168.0.0/24 . Since, the /32 for the int g0/1 represents the hosts itself and g0/1 r with /24 masks represents the network containing the ".2" interface. The ans is g0/1.
I think the reason of answer C is correct is because 192.168.0.55 fit the range of /24 with the longest prefix , while it's via 10.0.12.2 , choosing the longest prefix 10.0.12.1/32. Will get the answer, hope it will help u a bit !!
While I believe C is in fact correct, I don't think it's because of the reason you give.
A /32 in the table means it's a host route. 10.0.12.1 is a end host.
10.0.12.0/24 contains 10.0.12.2 on the G0/1 interface.
Unless I'm understanding wrong
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