Refer to the exhibit. An IP subnet must be configured on each router that provides enough addresses for the number of assigned hosts and anticipates no more than 10% growth for new hosts. Which configuration script must be used? A. B. C. D.
Here we will do the following
with no more than 10% possible growth
R7 expects 923 + 92 = 1015 hosts
R8 expect 225 + 23 = 248 hosts
R9 expects 3641 + 364 = 4005 hosts
R7 must use SM /22 at-least or less
( which gives 1022 usable IPs)
R8 must use SM /24 or less
(which gives 254 usable IPs)
R9 must use SM /20 or less
(which gives 4094 usable IPs)
All answers are correct, but C uses /24 , /22 & /20 SM for router R7, R8 AND R9 respectively. C gives the most efficient use.
Remember the powers of 2 to solve the question quickly
1,2,4,8,16,32,64,128,256,512,1024,2048,4096
1015 approximated to 1024, 512 not enough
248 closest to 256
4005 closest to 4096
R7 needs 10 zeros and the rest are ones in its SM, starting from the right
11111111.11111111.11111100.00000000 >>> 255.255.252.0
R8 needs 8 zeros and the rest are in its SM
11111111.11111111.11111111.00000000 >>> 255.255.255.0
R9 needs 12 zeros and the rest are ones in its SM
11111111.11111111.11110000.00000000 >>> 255.255.240.0
select the router with the lowest number of hosts, wich is r8, for 225 hosts it would be a minimun of 256 hosts wich is /24 wich is the only answer that has 255.255.255.0
upvoted 4 times
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