Refer to the exhibit. After applying this configuration to router R1, a network engineer is verifying the implementation. If all links are operating normally, and the engineer sends a series of packets from PC1 to PC3, how are the packets routed?
A.
They are distributed sent round robin to interfaces S0/0/0 and S0/0/1
The ad of 172.16.20.2 is default (1)
The ad of 10.0.0.2 is 20.
Because the match is the same, ( both /0) the router will compare AD. The lowest AD wins.
Assuming that the image has a typo on the first command, just before the mask (as @dosu01 as pointed out) and that the correct command was inserted as
"R1(Config)#ip route 0.0.0.0 0.0.0.0 172.16.20.2",
the route most packets will follow would be 172.16.20.2, due to the metric value 20 used on route 10.0.0.2 .
If it was not a typo, then the answer would be 10.0.0.2 (B).
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