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Exam 300-410 topic 1 question 416 discussion

Actual exam question from Cisco's 300-410

Question #: 416
Topic #: 1

Refer to the exhibit. A network is configured for EIGRP equal-cost load balancing, but the traffic destined to the servers is not load balanced. Link metrics from router R2 to R3 and R4 are the same. Which delay value must be configured to resolve the issue?

A. 2200 on R4 E0/1
B. 200 on R3 E0/1
C. 120 on R3 E0/1
D. 120 on R4 E0/1

Show Suggested Answer

Suggested Answer: C 🗳️

by jarz at Dec. 20, 2022, 10:32 p.m.

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elmorrre

Highly Voted 2 years, 3 months ago

Selected Answer: C

Delay shown at a R2 is a SUM of delays R2 (e0/0) and R3 (e0/1) via R2-R3 path and SUM of delays R2 (e0/0) and R4 (e0/1) via R2-R4 path Thus, it is 100 (tens of microseconds) + 100 (tens of microseconds) = 200 (tens of msec) = 2000 (microseconds) via upper path, and 100 + 120 (220 tens of msec = 2200) via lower path. For load balancing, we have to setup R3 e0/1 delay 120 (delay on an interface is setup in tens of microseconds) Finally, we will have 2200 msec summarized delay for 10.1.3.0 subnet on R2 Labbed it in GNS3.

upvoted 21 times

dapardo

1 year ago

if you are confused about B not been the right one, remember that delay is on tens of microseconds so 120 = 1200 microseconds

upvoted 6 times

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[Removed]

2 years, 1 month ago

Have you tried in the lab to configure the exact delay as R3 on R4? In my opinion at this point the router will make the necessary calculations and because bandwidth and delay are the same it will load balance them, therefore A.

upvoted 1 times

[Removed]

2 years, 1 month ago

After double checking it your logic is right

upvoted 1 times

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[Removed]

Most Recent 10 months, 1 week ago

Selected Answer: C

C is correct R3: 100 (1000) + 100 (1000) = 2000 R4: 120 (1200) + 100 (1000) = 2200 now we must make the delay of R3 path to 120 instead of 100 so that both paths match.

upvoted 4 times

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XBfoundX

10 months, 1 week ago

Yes the right one is C. I think that is an error of the image but I think that the router with the IP 10.1.2.3 is R3. We need to modify the Delay of the interface eth0/1 of R3 so 120 means ==> 1200 + 1000 = 2200 microseconds. With this configuration we got Equal cost load balancing So answer is C

upvoted 2 times

XBfoundX

8 months, 3 weeks ago

I also have labbed it and it works fine

upvoted 1 times

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[Removed]

10 months, 1 week ago

Selected Answer: C

C is correct R3: 100 (1000) + 100 (1000) = 2000 R4: 120 (1200) + 100 (1000) = 2200 now we must make the delay of R3 path to 120 instead of 100 so that both paths match.

upvoted 1 times

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pyrokar

2 years ago

Selected Answer: C

EIGRP default metric is 256*[(10^7/Min. Bandwidth)+delay/10] Repoted distance for R4 is 286720 Min. Bandwidth in kbps is 10^4 256*[(10^7/10^4)+delay/10] = 286720 delay for R4 = 120 Hence R3 must be adjusted to the same delay -> Answer C

upvoted 2 times

bk989

9 months, 1 week ago

to add it is total delay/10 so 1000+ 120 = 1120/10 = 120 10^/7 /10 ^ 4 = 1000 1000+120 = 286720/256

upvoted 1 times

bk989

9 months, 1 week ago

the 1000 is the delay on the R2 e0/0 interface. Now we need to add 120 delay in the path.

upvoted 1 times

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HungarianDish_111

2 years ago

Selected Answer: C

Agree with elmorre. The scenario is taken from here, where it is explained in detail: https://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing-protocol-eigrp/13673-14.html

upvoted 3 times

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ellen_AA

2 years, 4 months ago

Probably B is correct. It says, 'Link metrics from router R2 to R3 and R4 are the same' which means, the difference happen after when R2 and R3 to reach destination of 10.1.3.0/24. to make total delay equal, add 200 delay on interface facing the subnet 10.1.3.0/24 on R3.

upvoted 1 times

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Patrick1234

2 years, 4 months ago

I think the given answer is correct. When you configure this: interface eth 0/1 delay 200 And do a show ip eigrp topology, the value 200 will be multiplied with 10, so it will tell you 2000, which is equal to the 2000 of the other neighbor.

upvoted 2 times

smayus

2 years, 3 months ago

Why is it going to be multiplied by 10. Cumulative delay along the paths is divided by 10 at the end. This question seems to be very tricky and unclear.

upvoted 2 times

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jarz

2 years, 5 months ago

Selected Answer: A

it's clear the only difference between the two routers is the Total delay, R3 is 2000 and R4 is 2200.

upvoted 3 times

ellen_AA

2 years, 4 months ago

it should be 2000 on R4 E0/1 to make it equal R3 delay of 2000

upvoted 3 times

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