The configuration of R1 to R6 are posted below for your reference, useless lines are omitted: What is the advertised distance for the 192.168.46.0 network on R1?
Suggested Answer:C🗳️
To check the advertised distance for a prefix we cannot use the "show ip route" command because it only shows the metric (also known as Feasible Distance). Therefore we have to use the "show ip eigrp topology" command: : Although the "show ip eigrp topology" does not work in the exam but the "show ip eigrp 1 topology" does work so please use this command instead and
Update - we will find out the advertised distance on R1. There are two parameters in the brackets of 192.168.46.0/24 prefix: (1810944/333056). The first one "1810944" is the Feasible Distance (FD) and the second "333056" is the Advertised Distance (AD) of that route -> A is correct. Just for your reference, this is the output of the "show ip route" command on R1: In the first line: D 192.168.46.0/24 [90/ 1810944] via 192.168.12.2, 00:10:01, Ethernet0/0 The first parameter "90" is the EIGRP Administrative Distance. The second parameter "1810944" is the metric of the route 192.168.46.0/24. R1 will use this metric to advertise this route to other routers but the question asks about "the advertised distance for the 192.168.46.0 network on R1" so we cannot use this command to find out the answer.
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black_chechos
5 years, 6 months ago