Exam 200-901 topic 1 question 406 discussion

The goal is to add the current directory (pwd, which prints the working directory) to the PATH variable without overwriting the existing PATH. The correct way to do this in a Bash shell is: export PATH=$PATH:$(pwd) • export → Ensures that PATH is available to subshells. • $PATH → Keeps the existing PATH values. • $(pwd) → Expands to the current working directory. • : → Acts as a separator between paths in PATH. Its C if its a copy error. This command appends the current directory to the PATH, allowing any executables in this directory to be run without specifying their full path.

I would choose C, because I think there's a typo must be pwd not pwc1, all other alternatives are wrong.

C. export PATH=$PATH:$(pwd) The correct command to add the current directory to the PATH without overwriting the current PATH in the Bash shell is: C. export PATH=$PATH:$(pwd) I think the answer had an issue with OCR (converting image to text)

The correct answer is export PATH=$PATH:$(pwd) Maybe A or C has a typo.

Tested on Centos: answer C returns error, answer A works: export PATH=$PATH:$(pwc1) -bash: pwc1: command not found

Answer C is accurate, just some bad OCR. When you set a variable in Linux, you don't use the $, so A is wrong. You only use a $ when referring to a variable, so C should be: export PATH=$PATH:$(pwd) pwc1 would be a very common mistake for an OCR algo, c1 looks visually similar to d.

C doesn't make sense, gotta be A

why not A C does not make any sense