Given MAC = 50 00 00 04 00 00
To make it EUI-64 IPv6, insert FFEE in the middle of the MAC, so it will become: 50 00 00 FF FE 04 00 00
After this, "5" in binary will be written as "0101" and "0" in binary as "0000" OR we can say "50" in binary can be written as 01010"0"0. Now, flip the 7th bit, so it will become "010100"1"0" and now this "010100"1"0" can again be written in decimal as "52" after flipping the 7th bit. So, finally it will become: 52 00 00 FF FE 04 00 00
And our EUI-64 IPv6 will be: 2001:db8::5200:00FF:FE04:0000 /64
5 in binary is 0101
0 in binary is 0000
So, 50 in binary is 0101 0000
Flipping the 7th bit:
Original: 0101 0000
We change the second digit from left (0 to 1):
Result: 0101 0010
Converting the result back to hexadecimal:
0101 in binary is 5 in hex
0010 in binary is 2 in hex
So, 0101 0010 in binary is 52 in hexadecimal
MAC to EUI-64 conversion
SCENARIO: Router R1 has a MAC address of 5000.0004.0000 on its interface.
The objective is to calculate the corresponding EUI-64 address based on this MAC address.
Step #1: Split the MAC address in the middle:
5000.00 04.0000
Step #2: Insert FF:FE in the middle:
5000.00FF.FE04.0000
Step #3: Change the format to use a colon delimiter:
5000:00FF:FE04:0000
Step #4: Convert the first eight bits to binary:
5 0 -> 0101 0000
Step #5: Flip the 7th bit:
00000000 -> 0011 0010
Step #6: Convert these first eight bits back into hex:
0011 0010 -> 52, which yields an EUI-64 address of 5200:00FF:FE04:0000
Why you give us this incorrect answer? The answer is D 'cause the 7th bit after the eui-64 was flipped from 0 to 1, making the address look like 5200! Please, stop putting this wrong answer. Let the comunity choose. Apparently we know things better than your imaginary experts.
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