Exam SK0-005 topic 1 question 191 discussion

INCORRECT: A. RAID 0 was configured by mistake. (RAID 0 would yield 4 drives x 200GB = 800GB) INCORRECT: B. RAID 5 was configured properly. (RAID 5 would yield 1 drive for parity overhead and 3 drives x 200GB = 600GB) INCORRECT: C. JBOD was configured by mistake. (JBOD [just a bunch of disks] would yield 4 drives x 200GB = 800GB) CORRECT: D. RAID 10 was configured by mistake. (RAID 10 would yield 2 mirrored sets of 2 drives x 200GB = 400GB)

Seems to be raid10 to me - 2 lots of mirrored disks, totalling 400MB usable!?

If a RAID 5 volume was set up using four 200GB drives and the resulting volume size is approximately 600GB, then: B. RAID 5 was configured properly. RAID 5 uses one disk's worth of space for parity, so in this setup with four 200GB drives, the usable space would be the equivalent of three drives (3 x 200GB = 600GB). The fourth drive's capacity would be used for parity.

B. RAID 5 was configured properly.

Go to: https://www.raid-calculator.com/default.aspx and calculate the usable storage. The answer is D.

4x200G would resulut in 400G usable if in raid10 (should be 600G usable in raid5 3x data disk and 1 for parity)

looking at this answer again, 3 of the 4 200gb drives would be combined to 200 Gb of usable storage with raid 5 config, prolly leaving one drive in raid 0. This is a total of 400 GB of useable space and therefore is B

The result of configuring a single RAID 5 volume out of four 200GB drives attached to the server using the maximum possible capacity would be a RAID 5 configuration properly set up. RAID 5 is a data storage virtualization technology that combines multiple physical disk drive components into one or more logical units for the purposes of data redundancy, performance improvement, or both. It uses block-level striping with distributed parity to achieve redundancy while improving performance by spreading data over multiple disks. In this case, using four 200GB drives in a RAID 5 configuration with block-level striping and distributed parity, the total available capacity would be approximately 600GB (400GB usable), which is the sum of the capacity of three drives minus the capacity of one drive (i.e., 3 x 200GB = 600GB - 200GB = 400GB). Therefore, the correct answer is B. RAID 5 was configured properly.

The best answer to this question is A. RAID 0 was configured by mistake. RAID 5 uses one of the drives for parity information, so the usable capacity of the four 200GB drives in a RAID 5 array should be around 600GB, not 400GB. The fact that the server reports using all four drives but with only 400GB of capacity suggests that the four drives were combined using a RAID 0 configuration instead of RAID 5. In a RAID 0 configuration, the capacity of the drives is combined without any redundancy or parity information, resulting in faster performance but no fault tolerance. Therefore, the best answer is that RAID 0 was configured by mistake.