A field technician is responding to a ticket about an animated sign with double images. One image is stationary, and the other image is live. Which of the following is the cause of the issue?
Display burn-in occurs when a static image is left on a screen for a long time, causing the pixels to wear out unevenly and retain a ghost image even when new content is displayed. This issue can result in double images, where the "burned-in" stationary image persists alongside new, live content. This problem is more common in older displays or those used for static signage. Replacing the display cable or adjusting color settings would not address the underlying cause of uneven pixel wear, and burned-out bulbs would likely result in a loss of image clarity or brightness, not double images.
References: Display burn-in is a well-documented phenomenon in display technology, particularly affecting screens used for signage with static elements.
C. Display burn-in
Display burn-in occurs when static images are displayed on a screen for an extended period. This can cause the image to become permanently etched onto the screen, resulting in a ghost image or shadow. In the case of the animated sign, the stationary image is likely causing burn-in on the display.
GG
Burn-in happens when an image kind of never goes away and is engraved into the display. It's usually faint for the most part.
upvoted 3 times
...
This section is not available anymore. Please use the main Exam Page.220-1101 Exam Questions
Log in to ExamTopics
Sign in:
Community vote distribution
A (35%)
C (25%)
B (20%)
Other
Most Voted
A voting comment increases the vote count for the chosen answer by one.
Upvoting a comment with a selected answer will also increase the vote count towards that answer by one.
So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.
JonHin
5 months, 2 weeks agoNate_A
8 months, 3 weeks ago12fb6f7
1 year, 1 month ago