Exam N10-009 topic 1 question 124 discussion

B 95 is the brodcast address

answer is B 255.255.255.240 is /28, and has 16 addresses Network Address: 10.0.0.80 First usable: 10.0.0.81 *Web Server* Last usable: 10.0.0.94 Last IP / Broadcast IP: 10.0.0.95 *Router* Next network: 10.0.0.96 Maybe the network admin wanted to assign the router 10.0.0.94 (last usable IP for network 10.0.0.80/28), thankfully this shouldn't happen because companies always emphasise attention to detail on job postings Dennizje is right

A, The router interface is configured with IP 10.0.0.95 and a subnet mask of 255.255.255.240, which translates to a /28 subnet (or 16 IP addresses per subnet). The address range for the subnet that includes 10.0.0.95/28 is 10.0.0.80 - 10.0.0.95. However, 10.0.0.81 is within this subnet, but 10.0.0.95 is the broadcast address for the subnet, meaning the router's configuration on 10.0.0.95 isn't appropriate for routing directly to 10.0.0.81.

It's B. The Network address is 10.0.0.80. So the printer is NOT in a different subnet. Subnet is /28. Last octet is 01011111. From the last octet, the first 4 are static. Since the last 4 bits are all occupied, it is the last possible IP address of the subnet before moving on to the next. The last possible IP address is the broadcast address. People voting A are just assuming because it's a common answer on practice tests.