DRAG DROP - Place each of the following passwords in order of complexity from least complex (1) to most complex (4), based on the character sets represented. Each password may be used only once. Select and Place:
26 lowercase, 26 uppercase,10 digits, 33 characters classified as ASCII Punctuation & Symbols
zv3rl0ry each char has 36 symbols i.e. 36^8 permutations
Zverlory each char has 52 symbols 52^8 permutations
Zverl0ry each char has 62 symbols 62^8 permutations
Zv3r!0ry each char has 95 symbols 95^8 permutations
The question is about complexity i.e. entropy. A password cracker is not a true test of entropy. The time it takes for software depends on how the software is written not necessarily the entropy of the password.
Passed the EXAM, about 10 percent of the ABCD questions were on the actual test, all PBQs were really the only thing that were on the test. Everything else was either reworded completely or new. I guess its a given now that PT0-001 wont be in commission within the next couple months.
zv3rl0ry lower case and digits 24+10 symbols per char
Zverlory upper and lower case 48 symbols per char
Zverl0ry upper, lower, digits 58 symbols per char
Zv3r!0ry upper, lower, digits, symbols dunno how many symbols there are but the is the most complex from a bruteforce perspective (not dictionary necessarily)
I would go for,
Zverlory > Upper case Lower case > 47 hours
Zverl0ry > Numbers Upper case Lower case > 4 days
zv3rl0ry > Numbers Lower case > 6 days
Zv3r!0ry > Numbers Upper case Lower case Symbols > 4 months
Do not rely on the password strength test to answer this full question as different password strength tests would provide different results depending on its character configuration.
Please see below for the justification,
----
https://www.my1login.com/resources/password-strength-test/
Zverlory > Upper case Lower case > 47 hours
Zverl0ry > Numbers Upper case Lower case > 4 days
zv3rl0ry > Numbers Lower case > 6 days
Zv3r!0ry > Numbers Upper case Lower case Symbols > 4 months
https://www.security.org/how-secure-is-my-password/
zv3rl0ry > 1min
Zverlory > 22min
Zverl0ry > 1 hour
Zv3r!0ry > 8 Hours
https://password.kaspersky.com/
Zverlory > 6 days
Zverl0ry > 12 days
zv3rl0ry > 12 days
Zv3r!0ry > 12 days
However, the question mentioned the order should be based on the character set and
I would go for:
Zverlory - 2 character types
zv3rl0ry - 2 character types
Zverl0ry - 3 character types
Zv3r!0ry - 4 character types
The question is about complexity i.e. entropy. A password cracker is not a true test of entropy. The time it takes depends on how the software is written not necessarily the entropy of the password.
Passed the exam today with 835 points Total 75 questions in 1 hours.
11 questions are new!
I remember a new question: how to remove command history in linux? right answer is “history -c”.
We'll meet again at the CISSP or OSCP? exam Thank you all very much!!!!!
any ideas
A penetration tester discovers during a recent test that an employee in the accounting department has been making changes to a payment system and redirecting money into a personal bank account. The penetration test was immediately stopped. Which of the following would be the BEST recommendation to prevent this type of activity in the future?
A. Enforce mandatory employee vacations
B. Install video surveillance equipment in the office
C. Implement multifactor authentication
D. Encrypt passwords for bank account information
Isn't this supposed to be the order based on the character set?
zv3rl0ry (26 lowercase + 10 digits)
Zverlory (26 lowercase + 26 uppercase)
Zverl0ry (26 lowercase + 26 uppercase + 10 digits)
Zv3r!0ry (26 lowercase + 26 uppercase + 10 digits + Special charaters)
In terms of entropy H, which is equal to L*Log(N)/Log(2), we get a new order:
zv3rl0ry: 41 (plays with 36 chars: lc + num)
Zverlory: 45.6 (plays with 52 chars: lc + uc)
Zverl0ry: 47.6 (plays with 62 chars: lc + uc + num)
Zv3r!0ry: 52.4 (plays with 94 chars: lc + uc + num + symb)
This is not helping much because we now have 3 valid choices but this one makes a lot of sense when comparing the number of characters per set.
It depends which service you look at. The numbers from msxdos3 are good from passwordmeter.com. Using www.my1login.com, I get:
Zverlory cracked in 47 hours
ZverlOry cracked in 4 days
zv3rlOry cracked in 6 days
Zv3r!Ory cracked in 4 months
To me Zverl0ry(uc, lc, 1num) is more complex than zv3rl0ry(lc, 2num). I'll have to check if several numbers is better then large cap.
I would go
Zverlory
zv3rl0ry
Zverl0ry
Zv3r!0ry
zv3rl0ry : 2 character sets only digits and lowercase
Zverl0ry : 3 character sets digits , lowercase and uppercase that is harder to crack
I agree I would go with the same order. I check The password meter website to measure the complexity of the password. Zverl0ry is harder to crack compared to zv3rl0ry.
http://www.passwordmeter.com
*Note: do not measure your own actual passwords using this site, not trusted! :)
Is that a zero or an uppercase O - it might make a difference. Assuming an uppercase O.
Zverlory (only u/c is first char)
ZverlOry (two u/c one in the middle)
zv3rlOry (l/c u/c and digit)
Zv3r!Ory (l/c u/c digit and spec char)
If it's a zero, maybe:
Zverlory (l/c and u/c)
Zverl0ry (l/c u/c and digit)
zv3rl0ry (l/c u/c and 2 digits)
Zv3r!0ry (l/c u/c 2-digits and spec char)
I would switch Zverl0ry & zv3rl0ry personally, zv3rl0ry doesn't actually have any uppercase letters. l/c and 2 digits only
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