A technician is configuring a new server with an IP address of 10.35.113.47 on the 10.35.112.0 subnet to allow for the maximum number of hosts. When configuring network settings, which of the following is the correct subnet mask?
Now, I had to think about it for a moment, thinking that we only had to find the correct mask based on the subnet and IP addresses, then both 255.255.240.0 and 255.255.248.0 could be possible. I just did not bother to finish the actual question, the key aspect being: the MAXIMUM NUMBER OF HOSTS...
Answers A and B are IP addresses so we can get rid of them, not valid subnet masks.
Since the values 10 and 35 are the only ones repeated in both IP addresses we have to assume that the subnet mask will start with two full octet values: 255.255. That rules out answer E.
The number values for each bit of the third octet would run as follows:
128 192 224 240 248 252 254 255
1 1 1 1 1 1 1 1
a subnet mask of 255.255.248.0 leaves us with three bits for hosts (2046).
a subnet mask of 255.255.240.0 leaves us with 4 bits for possible host calculation (4094) and is the answer.
Your answer is correct, however, answer A and B are not just IP addresses.. these are another way of writing subnet mask. '/24' is equal to 255.255.255.0, '/30' is equal to 255.255.255.252. cheers
if you got 112.1 - 119.254, you used the 248, yes. However, the ip range of 112.1 - 1126.254 is the 240 subnet, or /28.. which gives you more IPS.. so the 240 is correct, yes?
Question asked for max. # of host...so count the host bits....from 3rd octet to forth octet.
with 255.255.240.0 you have 12 host bits, therefore, 2 to 12th power minus 2 equals 4,092.
unlike 255.255.248.0 ....you will have 11 host bits, that 2 to the 11th power minus 2 equal 2,046
the question didn't ask about ranges, broadcast or 1st and last. This is about counting binary 1's and 0's....mostly the 0's (hosts) in this case.
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