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Exam CAS-004 topic 1 question 48 discussion

Actual exam question from CompTIA's CAS-004
Question #: 48
Topic #: 1
[All CAS-004 Questions]

A security engineer estimates the company's popular web application experiences 100 attempted breaches per day. In the past four years, the company's data has been breached two times.
Which of the following should the engineer report as the ARO for successful breaches?

  • A. 0.5
  • B. 8
  • C. 50
  • D. 36,500
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Suggested Answer: A 🗳️
by dangerelchulo at Aug. 30, 2022, 7:50 a.m.

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dangerelchulo
Highly Voted 2 years, 2 months ago
Selected Answer: A
this is the formula for Annual Rate of Occurrence (ARO) ARO = Incidents / Year ARO = 2/4 = 0.5
upvoted 10 times
kycugu
1 year, 11 months ago
correct, I couldn't agree more.
upvoted 4 times
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ninjachuleta
Most Recent 6 months, 3 weeks ago
Answer: A 2 Incidents / 4 Years = .5
upvoted 1 times
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BiteSize
1 year, 3 months ago
Selected Answer: A
Math is hard Source: Verifying each answer against Chat GPT, my experience, other test banks, a written book, and weighing in the discussion from all users to create a 100% accurate guide for myself before I take the exam. (It isn't easy because of the time needed, but it is doing my diligence)
upvoted 2 times
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Mr_BuCk3th34D
1 year, 10 months ago
To calculate the ARO for successful breaches, the security engineer should divide the number of successful breaches (2) by the number of years that the data has been breached (4), and then multiply the result by the number of days in a year (365). This would give the following equation: ARO = (2 / 4) * 365 = 0.005 Therefore, the ARO for successful breaches is 0.005, or approximately 0.5% per year
upvoted 4 times
rmwilsn
1 year, 7 months ago
are you not aware that 0.005 and 0.5 are drastically different numbers?
upvoted 8 times
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BotWayne
2 years, 1 month ago
Selected Answer: A
Agree with @dangerelchulo. They're trying to confuse you by throwing in other numbers. Only focus on the actual number of breaches over the number of years.
upvoted 2 times
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Community vote distribution
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C (25%)
B (20%)
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