A technician is building a lab to learn storage redundancy techniques. Which of the following is the MOST cost-effective method the technician can deploy?
D. JBOD (Just a Bunch Of Disks)
JBOD is usually the most cost-effective option because it doesn't involve any specialized hardware or RAID controllers. It simply aggregates individual hard drives without any redundancy or striping. While it lacks redundancy and fault tolerance features, it can still be a suitable option for learning storage concepts and experimenting with redundancy techniques at a lower cost compared to the other options listed.
FCoE (Fibre Channel over Ethernet), Hardware RAID, and Software RAID all involve additional hardware or software components, which can increase the overall cost.
C. Software RAID
Software RAID is the most cost-effective method of deploying storage redundancy techniques in a lab environment. Software RAID uses the server's CPU and memory to manage the disk redundancy, and can be implemented without additional hardware or specialized equipment. Most operating systems have built-in support for software RAID, making it easy to set up and configure.
Hardware RAID is a more expensive option, as it requires specialized RAID controllers and storage devices that support RAID. FCoE (Fibre Channel over Ethernet) is a high-performance network protocol used to connect storage devices to servers, but it requires specialized network hardware and is not a cost-effective option for a lab environment. JBOD (Just a Bunch Of Disks) is a storage configuration where disks are presented to the operating system as individual drives, and it does not provide any redundancy or fault tolerance.
Software RAID advantages:
- Less expensive
- Fewer components to manage
Disadvantages:
- Less flexible
- Consumes system and OS resources
Hardware RAID advantages:
- Faster
- More flexible
- Does not consume server resources
Disadvantages:
- More expensive
- More components to manage
- More complex
The Official CompTIA Server+ Study Guide (Exam SK0-005) page 114.
JBOD is no data redundancy, and regardless of the number of disks in the system, if the data is spanned across the disks, the loss of a single disk means the loss of all data.
Software RAID would be the most cost effective as it will use existing HDs to create the environment. Not to mention we are looking to learn storage redundancy. JBOD is the exact opposite of this.
https://www.techtarget.com/searchstorage/definition/software-RAID-software-redundant-array-of-independent-disk#
I think the correct answer is C. JBODs don't have redundancy.
upvoted 2 times
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