Exam N10-007 topic 1 question 338 discussion

OverCapacity- C is more likely the correct answer. there are higher chances that a student connect more than one device to the Wifi. Frequency, on the other hand, will be an issue of intermittent connection, or low signals.

I gotta agree with Shawnf. B is the BEST answer. A is possible... but that would impact 1/2 of the students... Q doesn't stipulate 1/2 of students, just says "several". C doesn't seem technical enough, but again is possible. D is also possible, but two WAPs in a lecture hall should be positioned to avoid distance issues, I mean just HOW BIG is this lecture hall?! However, B, using 802.11g devices require you know "g" uses 2.4 GHz and "ac" uses 5.0 GHz and the two are not compatible. Plus "several" students could have older devices, not half, not everyone, but several is reasonable. It makes the most sense if the Q is testing your knowledge of WiFi. Keep in mind, exam dumps are mostly created by test takers' "memory". So the questions are most likely not exact, nor are the answers always correct. Use them for what they are, do not memorize answers, verify and research what you don't know and you'll do great on the exam!

Yeah remember they are asking for a limit so overcapacity is likely what they are referring to. So this means a limit is for per student and if each of them have more than one device then acourse the limit is reached. Answer is C.

Should be C. Just think about it. Each student probably has a laptop and a phone that they're going to connect to wifi. And 802.11ac is backwards compatible with 802.11g. "802.11ac utilizes dual band wireless technology, supporting simultaneous connections on both the 2.4 GHz and 5 GHz Wi-Fi bands. 802.11ac offers backward compatibility to 802.11b/g/n and bandwidth rated up to 1300 Mbps on the 5 GHz band plus up to 450 Mbps on 2.4 GHz."

802.11ac offers backward compatibility to 802.11b/g/n and bandwidth rated up to 1300 Mbps on the 5 GHz band plus up to 450 Mbps on 2.4 GHz

i thought 802.11 ac was backwards compatable?

Theres only two devices in the room. 2 x 802.11ac. There is no 802.11g device in the room to connect to. The answer to this is 100% wrong

Question sucks but answer is correct if it is 802.11AC which only operates at 5Ghz, that has a greatly reduced range. But again it is highly possible students are connecting phones, laptops etc which would be overcapacity

Students trying to connect with 802.11g devices would be unable to connect.

It could be distance. I attended Purdue University (a long time ago) and some of the lecture halls were huge (more like auditoriums) and in those lecture halls coverage with the 802.11ac range limit of 35m/115ft could conceivably prove inadequate when using only 2 APs. I like 'B' though because if some of the students had laptops with 802.11g devices which operate only on 2.4GHz, they would not be able to communicate with 802.11ac APs which only operate on 5.0 GHz. That being said, I don't know how likely that scenario would be given that college students usually have the latest and greatest tech devices.

Distance limitations are preventing the students from connecting. This is the right answer since the hall can hold only 50 devices against 100 students. Due to the capacity of the hall some students are outside the hall which limit the signal from a distance.

I'll let any of the 100 students sign in with his/her SID and LastName on a Captive portal just to avoid the overcapicity :). 802.11ac can go for 235 meters in distance may be the antennas are Omnidirectional and those several student whos complaining are sitting right beneath under the WAP :)

Correct answer is B. 802.11g use only 2.4GHz frequency, 802.11ac use only 5GHz frequency.

I believe the answer is B. You can't connect wireless G to wireless A/C.

Many students would have a laptop and mobile phone connecting to the wifi. A full lecture hall would definitely saturate the WAPs.

I was going to say channel overlap, but that wasn't an option.

802.11ac uses only 5GHz frequency and the question doesn't say anything abt the device type the students are using. So i think the distance is the correct answer here.