Exam 312-50v10 topic 1 question 191 discussion

Actual exam question from ECCouncil's 312-50v10

Question #: 191
Topic #: 1

The network in ABC company is using the network address 192.168.1.64 with mask 255.255.255.192. In the network the servers are in the addresses
192.168.1.122, 192.168.1.123 and 192.168.1.124.
An attacker is trying to find those servers but he cannot see them in his scanning. The command he is using is: nmap 192.168.1.64/28
Why he cannot see the servers?

A. He needs to change the address to 192.168.1.0 with the same mask
B. He needs to add the command ""ip address"" just before the IP address.
C. He is scanning from 192.168.1.64 to 192.168.1.78 because of the mask /28 and the servers are not in that range.
D. The network must be down and the nmap command and IP address are ok

Show Suggested Answer

Suggested Answer: C 🗳️

by sandman310323 at Aug. 24, 2020, 5:08 p.m.