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Exam 312-49 All Questions

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Exam 312-49 topic 1 question 229 discussion

Actual exam question from ECCouncil's 312-49
Question #: 229
Topic #: 1
[All 312-49 Questions]

Given the drive dimensions as follows and assuming a sector has 512 bytes, what is the capacity of the described hard drive?
22,164 cylinders/disk
80 heads/cylinder
63 sectors/track

  • A. 53.26 GB
  • B. 57.19 GB
  • C. 11.17 GB
  • D. 10 GB
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Suggested Answer: A 🗳️

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JKCY
11 months ago
512 × 63 × 80 × 22164 =57,193,758,720 bytes =57.19GB
upvoted 2 times
larajorge
8 months, 1 week ago
Your multiplication is correct, but the amount of bytes in the result does NOT equal 57.19 GB. 57,193,758,720 bytes / 1024 (for KB) / 1024 (for MB) / 1024 (for GB) = 53.26 GB. Answer A is correct.
upvoted 6 times
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