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Exam 312-50 topic 4 question 42 discussion

Actual exam question from ECCouncil's 312-50
Question #: 42
Topic #: 4
[All 312-50 Questions]

What is the correct PCAP filter to capture all TCP traffic going to or from host 192.168.0.125 on port 25?

  • A. tcp.src == 25 and ip.host == 192.168.0.125
  • B. host 192.168.0.125:25
  • C. port 25 and host 192.168.0.125
  • D. tcp.port == 25 and ip.host == 192.168.0.125
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Suggested Answer: D 🗳️
by Luukman at Sept. 12, 2021, 6:45 p.m.

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Eyebullet
1 month, 1 week ago
Selected Answer: C
C is the right answer. This is not wireshark.
upvoted 1 times
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dehamedah
1 year, 3 months ago
Selected Answer: C
C is the right answer
upvoted 1 times
NikoTomas
1 year, 1 month ago
No, D is correct: tcp.port == 25 and ip.host == 192.168.0.125. Syntax of C does not work in Wireshark (it is not tcpdump!) and moreover C does not specifi TCP, which is requirement in the question.
upvoted 1 times
Chogi_
7 months, 3 weeks ago
but ip.host == 192.168.0.125 is not a valid Wireshark filter. Wireshark uses ip.addr to refer to both source and destination IP addresses, not ip.host.
upvoted 1 times
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