No, D is correct: tcp.port == 25 and ip.host == 192.168.0.125.
Syntax of C does not work in Wireshark (it is not tcpdump!) and moreover C does not specifi TCP, which is requirement in the question.
but ip.host == 192.168.0.125 is not a valid Wireshark filter. Wireshark uses ip.addr to refer to both source and destination IP addresses, not ip.host.
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