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Exam 101 topic 1 question 305 discussion

Actual exam question from F5's 101
Question #: 305
Topic #: 1
[All 101 Questions]

An LTM has the 3 virtual servers, 2 SNATs, four self IP addresses defined and the networks shown in the graphic below. Selected options for each object are shown below. Settings not shown are at their defaults. Assume port exhaustion has not been reached.

A connection attempt is made with a source IP and port of 10.20.10.50:2222 and a destination IP and port of 10.10.2.102:80.
When the request is processed, what will be the source and destination IP addresses?

  • A. Source IP: 10.20.10.50; Destination IP: pool member in the 172.16/16 network
  • B. Source IP: 172316.20.50; Destination IP: pool member in the 182.16/16 network
  • C. Source IP: 192.168.1.1; Destination IP: pool member in the 192.168/16 network
  • D. The request will be dropped.
  • E. Source IP: 10.20.10.50; Destination IP: pool member in the 192.168/16 network
  • F. Source IP: 182.16.1.1; Destination IP: pool member in the 172316/16 network
  • G. Source IP: 192.168.10.50; Destination IP: pool member in the 192.168/16 network
  • H. Source IP:192.168.10.50; Destination IP: pool member in the 192.168./16 network
Show Suggested Answer Hide Answer
Suggested Answer: F 🗳️
by espositop2004 at Dec. 8, 2020, 10:14 a.m.

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Danielseyoum
Highly Voted 2 years, 10 months ago
F is the answer ignoring the typo: Source IP: 172.16.1.1; Destination IP: pool member in the 172.16/16 network
upvoted 5 times
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azzawim
Most Recent 1 week ago
answer F because automap is in used
upvoted 1 times
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samqq
11 months, 2 weeks ago
Selected Answer: A
I think it is A since the destination IP match most specific range. So the only the first VS is processed. So no SNAT. source address no change and destination is a pool member
upvoted 1 times
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juantron
2 years, 3 months ago
Answer is F, but ignoring the typo. When using a SNAT pool source address translation, the SNAT pool must contain SNAT translations assigned to the same traffic group as the virtual server’s virtual address. The only selfIP that maps traffic group of this SNAT is 172.16.1.1. Virtualserver1 accepts traffic because it contains the destination address and port 80 of the request, so it wins the battle against virtualserver2, with wildcard port.
upvoted 2 times
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GHChee
3 years ago
correct answer is A?
upvoted 1 times
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espositop2004
3 years, 4 months ago
Why E is not correct ??
upvoted 1 times
mpro
3 years, 3 months ago
I believe it is
upvoted 1 times
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intelligerian
3 years, 3 months ago
because it is listening on all ports. The other virtual server is listening only for port 80
upvoted 1 times
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