Exam NSE7_SDW-7.2 topic 1 question 67 discussion

Actual exam question from Fortinet's NSE7_SDW-7.2

Question #: 67
Topic #: 1

Refer to the exhibit.

The exhibit shows the SD-WAN rule status and configuration.

Based on the exhibit, which change in the measured packet loss will make T_INET_1_0 the new preferred member?

A. When T_INET_1_0 has 4% packet loss.
B. When T_INET_0_0 has 12% packet loss.
C. When T_INET_0_0 has 4% packet loss.
D. When all three members have the same packet loss.

Show Suggested Answer

Suggested Answer: D 🗳️

by Mellon at Oct. 4, 2024, 4:22 a.m.

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0x194

5 months, 1 week ago

- If you set `link-cost-threshold` to `0`, then FortiGate performs a strict metric comparison -> link-cost-threshold(0) - The member with the best metric becomes the preferred (tiebreaker) -> priority-members 5 3 4 All members need to have the same packet loss; otherwise, T_INET_1_0 (5 T_INET_1_0) can't get the preferred member through priority (tiebreaker). Study Guide Page 202

upvoted 1 times

0x194

5 months, 1 week ago

Therefore, the correct answer is D: When all three members have the same packet loss.

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aa0v1snjr9

6 months, 1 week ago

i don't understand the answer it's D. When all three members have the same packet loss??

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kappa915

6 months, 1 week ago

Selected Answer: D

D is correct, check ccie8122's answer

upvoted 1 times

aa0v1snjr9

6 months, 1 week ago

continue to not understand. because seems that the answer should be A because win tie breaker... but is signed D.. where itàs written all members have the same packet loss..

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ccie8122

6 months, 4 weeks ago

Selected Answer: D

Since the threshold is 0% and T_INET_1_0 (member 5) has the highest priority, as long as the other two links have the same or higher packet loss as T_INET_1_0, T_INET_1_0 wins the tie breaker.

upvoted 2 times

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