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Exam JN0-102 topic 4 question 14 discussion

Actual exam question from Juniper's JN0-102
Question #: 14
Topic #: 4
[All JN0-102 Questions]

Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?

  • A. 192.168.100.48
  • B. 192.168.100.16
  • C. 192.168.100.0
  • D. 192.168.100.32
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Suggested Answer: D 🗳️
Network is a class C network: 192.168.100.32/27
Binary: 11000000.10101000.01100100.001 00000
=
by lugiricy at April 4, 2025, 5:04 p.m.

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