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Exam AZ-700 topic 2 question 36 discussion

Actual exam question from Microsoft's AZ-700
Question #: 36
Topic #: 2
[All AZ-700 Questions]

SIMULATION
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Lab Instance: 12345678
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You need to ensure that subnet 4-3 can accommodate 507 hosts.

To complete this task, sign in to the Azure portal.

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mabalon
Highly Voted 1 year, 3 months ago
/23 can fit 507 addresses. 512 hosts - 5 reserved = 507. The reserved ip address are .0 .1 .2 .3 and .255
upvoted 10 times
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Nagachn
Most Recent 3 weeks, 6 days ago
How do we know which vnet subnet4-3 belongs to? because we can't directly go to the subnets 4- 3. First navigate to the vnet and then choose the subnets
upvoted 1 times
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NahIgotPride
1 year, 1 month ago
Correct X.X.1.0/23 would be X.X.0.0 - X.X.1.255 (507 + 5 Azure reserved addresses)
upvoted 1 times
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Techbiz
1 year, 2 months ago
We need to borrow 9 host bits from the host bit and assuming that the default address space was a /16 CIDR, then we will need (2^9 - 5) to give us 507 ip address which is a /23
upvoted 1 times
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Sein
1 year, 3 months ago
/23 subnet won't be able to have 507 hosts, as azure reserves 5 IP addresses. You need /22 subnet.
upvoted 4 times
VeryOldITGuy
10 months, 3 weeks ago
Weird that MS says that if you create a /23, you get 507 + 5 Azure reserved addresses. x.x.0.0 to x.x.1.255 makes 510 IP addresses total in my calculator and even on calculator sites. Remove 0 at the beginning, 255 at the end and you are left with 508, then remove .1, .2 and .3 that Azure take and that leaves you 505. Where does the 507 come from?
upvoted 2 times
cda26aa
7 months, 1 week ago
2^9= 512 512-5 = 507
upvoted 1 times
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