Exam 98-381 topic 1 question 1 discussion

Incorrect first option,should initialize employee number as non blank value,otherwise how will the code ever enter the while loop (condition for entering is non blank value) to take the input. Also,the whole logic is to keep taking input when blank value is entered.

I suspect that employee_number = "sentinel" is hidden behind the last dropdown screenshot. The below code works. employee_number = "" parts = "" while employee_number != "sentinel": valid = False employee_number = input("Enter employee number (ddd-dd-dddd): ") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): valid = True employee_number = "sentinel" print(valid)

This would work with employee_number = "" and while employee_number != "sentinel": employee_number = "" parts = "" while employee_number != "sentinel": valid = False employee_number = input("Enter employee number (ddd-dd-dddd):- ") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): valid = True print(valid) break else: valid = False print(valid) else: valid = False print(valid) else: valid = False print(valid)

So heres my code, if your_momWeight == 69420: print("Your mom is absolutely messed up my guy, you gotta get that checked out.")

So this is my code: employee_number = "sentinel" parts = "" while employee_number != "": valid = False employee_number = input("Enter employee number (ddd-dd-dddd):- ") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): valid = True print(valid) break else: valid = False print(valid) else: valid = False print(valid) else: valid = False print(valid)

I think the first answer should be Employee_number = “” and the second answer as while employee_number != “sentinel”: because in programming, sentinel is the value that terminates a while loop so the second answer should be employee_number != “sentinel”: so if the user enters sentinel, it will terminate the while loop. Since the second answer is employee_number != “sentinel”: the first answer should be Employee_number = “” in order to run

Answer is correct: employee_number = "" parts = "" while employee_number != "": valid = False employee_number = input("Enter employee number (ddd-dd-dddd)") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): valid = True print(valid) else: valid = False print(valid) else: valid = False print(valid) else: valid = False print(valid)

#test this code employee_number = "sentinel" parts = "" while employee_number != "": valid = False employee_number = input("Enter employee number (ddd-dd-dddd)") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): valid = True print(valid)

Run the code: employee_number = "" parts = "" while employee_number == "": valid = False employee_number = input("Enter employee number (ddd-dd-dddd)") parts = employee_number.split('-') if len(parts) == 3: if len(parts[0]) == 3 and len(parts[1]) == 2 and len(parts[2]) == 4: if parts[0].isdigit() and parts[1].isdigit() and parts[2].isdigit(): print(valid)

There are two typos. The case on the "E" in the first "employee_number" is a typo - it should be lower case. The condition to enter the while loop should be "==" rather than "!="

this entire question doesnt make sense. Python is case sensitive so Employee_number is different from employee_number. so when it gets to while(employee_number != x) employee_number isnt a defined variable and the program will crash

Is that answer correct

It's correct. You are setting variables. It is checking to make sure Employee_Number is empty.

I don't understand the purpose of the while loop... The answer also seems incorrect because if you have while Employee_Number != "" right after you set Employee_Number to "", that code won't execute to initialize valid to false.