Exam 98-388 topic 1 question 34 discussion

55 55 Out of scope. El método "add" tiene como parámetro "anum" del tipo primitivo "int". Un parámetro de tipo primitivo siempre es pasado por copia, no por referencia, por lo tanto, aunque se altere dentro del método, al acabar el método el valor queda como estuviera al principio, sin alteaciones. Por eso la segunda respuesta es 55, no 56, ni 63. As for the variable "cnt", it is local to the "for" loop, and outside its keys it no longer exists.

I checked everything. Correct answer is: 55 56 Out of scope.

55 56 *the new anum is not saved, it is 55 when a new loop start) 10 (not sure, but i think when cnt reached 10, it ends the loop so code can run line06 which is out of scope for the loop) public static void main(String []args){ int anum = 55; for (int cnt = 0; cnt < 10; cnt++){ add(anum); System.out.println("line05 index" + cnt + " "+ anum); } System.out.println(anum); } public static void add(int anum){ anum++; System.out.println("line11 " + anum); }

55 63 out of scope

At line 11 anum would be 56 because anum++ already ran and cnt doesn't exist when line 6 executes.

wouldnt it be out of the scope for the last one? because the for loop has it's own scope and the maximum value cnt reaches is 9?