Exam DP-700 topic 1 question 50 discussion

Should be "A"; "B" will be result in string, not int: https://learn.microsoft.com/en-us/fabric/data-factory/parameters#parameter-and-expression-concepts

A @{pipeline().parameters.param1}" It does not alter the int type (since param1 is already int).

A is correct

https://learn.microsoft.com/en-us/fabric/data-factory/parameters#parameter-and-expression-concepts Parameter value Result "@pipeline().parameters.myString" Returns foo as a string. "@{pipeline().parameters.myString}" Returns foo as a string. "@pipeline().parameters.myNumber" Returns 42 as a number. "@{pipeline().parameters.myNumber}" Returns 42 as a string. "Answer is: @{pipeline().parameters.myNumber}" Returns the string Answer is: 42. "@concat('Answer is: ', string(pipeline().parameters.myNumber))" Returns the string Answer is: 42 "Answer is: @@{pipeline().parameters.myNumber}" Returns the string Answer is: @{pipeline().parameters.myNumber}.

B is wrong because "@{pipeline().parameters.myNumber}" Returns myNumber as a string.

@{pipeline().parameters.param1} This syntax correctly references the parameter param1 and ensures that it is treated as an integer value within the pipeline expression.

correct answer is a

B get string output

answer A will get int data output. answer B will get string.