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Exam AZ-303 topic 1 question 15 discussion

Actual exam question from Microsoft's AZ-303
Question #: 15
Topic #: 1
[All AZ-303 Questions]

DRAG DROP -
You have an Azure subscription that contains two virtual networks named VNet1 and VNet2. Virtual machines connect to the virtual networks.
The virtual networks have the address spaces and the subnets configured as shown in the following table.

You need to add the address space of 10.33.0.0/16 to VNet1. The solution must ensure that the hosts on VNet1 and VNet2 can communicate.
Which three actions should you perform in sequence? To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.
Select and Place:

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Suggested Answer:
Step 1: Remove peering between Vnet1 and VNet2.
You can't add address ranges to, or delete address ranges from a virtual network's address space once a virtual network is peered with another virtual network.
To add or remove address ranges, delete the peering, add or remove the address ranges, then re-create the peering.
Step 2: Add the 10.44.0.0/16 address space to VNet1.
Step 3: Recreate peering between VNet1 and VNet2
Reference:
https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-manage-peering

Comments

Chosen Answer:
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vuphongtran
Highly Voted 4 years, 4 months ago
The answer is probably correct, but I wonder how come the vnet2 has the subnet mask bits in its address space (/26) longer than those in its subnet (/24)?
upvoted 24 times
dzintarzkozbek
4 years, 4 months ago
It is shorter (less ips) no criminal here
upvoted 1 times
vuphongtran
4 years, 2 months ago
I believe they revised the question. Previously the address space has subnet mask length of /26 and subnet's is /16
upvoted 3 times
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attilaj
4 years ago
typo, just like new address space is 44 not 33 lol.
upvoted 6 times
SatishSharma
4 years ago
How 10.33.0.0/16 can be fit in Vnet 1 10.1.0.0/16, even with 44
upvoted 2 times
vaisat
3 years, 7 months ago
You are not fitting it in. You adding another another address space.
upvoted 1 times
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medi01
3 years, 10 months ago
Huh? /16 pins down first two sets of digits. It would fit 10.0.0.0/8
upvoted 1 times
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widurr
Highly Voted 4 years, 5 months ago
given answer is correct
upvoted 16 times
SanjSL
3 years, 7 months ago
Yes, it's correct as tested on a project
upvoted 2 times
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itvinoth83
Most Recent 3 years, 2 months ago
In Exam today, 28-02-2022
upvoted 1 times
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Molte
3 years, 4 months ago
Well in the question nothing says that Vnet1 and Vnet2 are actually peered right? So we could also assume removing perring is not nessacary or what do you think?
upvoted 1 times
TurboShot
3 years, 2 months ago
in the table it shows the peering.
upvoted 1 times
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sidk05
3 years, 2 months ago
Its mentioned in exhibit about peering.
upvoted 1 times
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rjcverar
3 years, 7 months ago
Appeared on 29.10.2021
upvoted 1 times
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vaisat
3 years, 7 months ago
Definitely correct answer.
upvoted 1 times
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plmmsg
3 years, 9 months ago
Answer is correct
upvoted 2 times
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syu31svc
3 years, 9 months ago
Address ranges can't be added or deleted from a virtual network's address space once it's peered with another virtual network. To add or remove address ranges, delete the peering, add or remove the address ranges, then re-create the peering manually. https://docs.microsoft.com/en-us/azure/architecture/networking/prefixes/add-ip-space-peered-vnet Answer is correct
upvoted 5 times
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janclintv
4 years ago
on exam 6/14.
upvoted 1 times
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MukeshAT0977
4 years ago
In exam today
upvoted 2 times
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sham21
4 years ago
Same question was in AZ-104 and I see almost one question match from AZ-104 dumps.
upvoted 1 times
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nfett
4 years ago
based on the logic in https://docs.microsoft.com/en-us/azure/architecture/networking/prefixes/add-ip-space-peered-vnet#add-the-ip-address-range ( Add the IP address range ) section the answer appears to be correct.
upvoted 2 times
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MikeAzure123
4 years, 1 month ago
The question did not state that peering already exists
upvoted 4 times
heamgu
4 years, 1 month ago
You should read the table, there is a column named Peering, it is referring that VNet1 and VNet2 are peering.
upvoted 11 times
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mr_sandy
4 years, 3 months ago
answer is correct but , it is probably a typo in the address space, it would be more sense to say /16. /24 wont fit into the /26 address space, the address space must be larger than the subnets within it.
upvoted 7 times
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SyntaxError
4 years, 5 months ago
The given solution is correct. REF: https://docs.microsoft.com/en-us/azure/architecture/networking/prefixes/add-ip-space-peered-vnet#add-the-ip-address-range
upvoted 2 times
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