Exam MD-101 topic 1 question 6 discussion

i think the answer is wrong , it should be no change needed . %Rand:1% means that it will only randomize one number, from 0-9. That means a total of 10 computers.

B = 10 = right https://www.anoopcnair.com/computer-name-during-windows-autopilot-intune/

I guess 5 was the item that was highlighted. If so, then yes the answer is B as 1 represents the number of digits that will be randomized.

I don't see anything underlined when viewing this in a web browser. If the 5 is underlined, then yes, it would be B, because %RAND:1% would give you a range from 0 - 9 (ten numbers total) so the number would change to 10.

Answer should be 10 devices, but we use %RAND:4% at our company which results in duplicate device names. Microsoft states that it will create unique device names but in my experience this is not true.

Rand:1 = 10 combinations, so B

I mean, how is this even a question :)

Answer B

Explaining the question: It says that if you use "%RAND:1%" then "You will be able to successfully run the package on on as much as 5 devices". That's wrong. You need to adjust it to: "on as much as 10 devices". So the answer B is correct. The expression: "underlined segment" is confusing because there is nothing really "underlined" there, maybe there is in a real exam. Here it's more like if a "condition" is true or not, and what's the right answer.

This took me a while, but I think I see it now, so for those still struggling with the wording. The portion you need to look at is; "You will be able to successfully run the package on as much as 5 devices." - Yes, this is technically correct, however, you are being asked if this exactly correct, which it isn't. The line should read. "You will be able to successfully run the package on as much as 10 devices." - Hence why the answer is B: 10

B. 10 is correct.

maybe someone can help me make sense of the mob discussion, the underlined can run up to 5 machines, the random generator will give us results for 10 machines, (0-9) so the answer would be A. No adjustment right? the way I see it, is that yes, the randomizer will give us 10, but doesn't the question state, leave it be if no change? or we CAN leave it if needed?

I agree with FlitZ. The answer B is correct because the underlined segment says that: "You will be able to successfully run the package on as much as 5 devices." However the %RAND:1% can be applied as much as 10 devices.

You will be able to successfully run the package on as many as 10 devices.

The answer is wrong in my understanding. The description of the answer even informs that it is wrong: Correct answer: B The device name uses a single random number (applied by %RAND:1%). This allows for 10 unique values (0 ג€" 9). Therefore, I believe the correct option is alternative A, No adjustment required, as %RAND:1% is enough to deploy up to 10 devices, and in the description it is saying that only 5. will be deployed.

Use %RAND:x% to generate x number of random digits in the name, where x must be a number less than 63. In this case, %RAND:1% means only 1 computer.