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Exam 70-741 All Questions

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Exam 70-741 topic 1 question 15 discussion

Actual exam question from Microsoft's 70-741
Question #: 15
Topic #: 1
[All 70-741 Questions]

Your company owns the public Internet IP address range of 131.107.20.0 to 131.107.20.255.
You need to create a subnet that supports four hosts. The solution must minimize the number of addresses available to the subnet.
Which subnet should you use?

  • A. 131.107.20.16/28
  • B. 131.107.20.16/30
  • C. 131.107.20.0/29
  • D. 131.107.20.0 with subnet mask 255.255.255.224
Show Suggested Answer Hide Answer
Suggested Answer: C 🗳️
http://jodies.de/ipcalc?host=131.107.20.0&mask1=29&mask2=

Comments

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coleman
Highly Voted 5 years, 7 months ago
/29 netmask provides 3bits of host ID, which supports (2^3)-2 = 6 hosts. The question requires to minimize the number of addresses, so we have to choose the longest netmask.
upvoted 11 times
Baldiico
4 years, 5 months ago
(2^3) - 2 = 4 host
upvoted 1 times
Baldiico
4 years, 5 months ago
My bad.ot will be 6 host the minimum there. But 4 host will definitely fit.
upvoted 1 times
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wilvarel
Highly Voted 5 years, 8 months ago
Network calculator ip: 131.107.20.0 last octet: 11111000 subnet mask: 111111111.11111111.11111111.11111000 (8x3)+5=29
upvoted 10 times
MCSA
5 years, 8 months ago
how did you get the (8x3)+5 from?
upvoted 2 times
Anton2020
5 years, 7 months ago
He/she counted the ones in the subnet mask
upvoted 3 times
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Pitch09
Most Recent 4 years, 7 months ago
The answer is correct. Address: 131.107.20.0 10000011.01101011.00010100.00000 000 Netmask: 255.255.255.248 = 29 11111111.11111111.11111111.11111 000 Wildcard: 0.0.0.7 00000000.00000000.00000000.00000 111 => Network: 131.107.20.0/29 10000011.01101011.00010100.00000 000 (Class B) Broadcast: 131.107.20.7 10000011.01101011.00010100.00000 111 HostMin: 131.107.20.1 10000011.01101011.00010100.00000 001 HostMax: 131.107.20.6 10000011.01101011.00010100.00000 110 Hosts/Net: 6
upvoted 4 times
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alexnt
4 years, 11 months ago
Variant: Which subnet should you use? A. 131.107.20.16 with subnet mask 255.255.255.248 B. 131.107.20.16/28 C. 131.107.20.0/27 D. 131.107.20.16/30 Offered Answer: A Is it correct?
upvoted 5 times
TA77
4 years, 10 months ago
Yes, because 248 = 11111000 which represents /29
upvoted 3 times
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Robbie
4 years, 10 months ago
yes this is correct
upvoted 3 times
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CassarJ
5 years, 5 months ago
/29 is the correct answer because it has 8 addresses (6 hosts when ID and broadcast are subtracted)
upvoted 8 times
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A (35%)
C (25%)
B (20%)
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