You need to implement an availability solution for DHCP that meets the networking requirements. Which two actions should you perform? Each correct answer presents part of the solution. NOTE: Each correct selection is worth one point.
A.
On DHCP1, create a scope that contains 25 percent of the IP addresses from Scope2.
B.
On the router in each office, configure a DHCP relay.
C.
DHCP2, configure a scope that contains 25 percent of the IP addresses from Scope1.
D.
On each DHCP server, install the Failover Clustering feature and add the DHCP cluster role.
E is a must so is part of the answer
A DHCP relay agent is a host or router that forwards DHCP packets between clients and servers
B is the other answer
Ok both links used to support the anweres here were not correct. one was a linux link and the other was incorrect. - the deploy and manage DHCP training page 6 discusses the dhcp failover and clustering- you cant have DHCP failover without a cluster...
https://learn.microsoft.com/en-us/training/modules/deploy-manage-dynamic-host-configuration-protocol/6-select-dynamic-host-configuration-protocol-high-availability-options
So the answers are d and e - but the issue with the other answer is why would you do split scope across this? the split scope is normally configed 75% 25% because its only used for backup. - of covering for a load... also the two offices are almost identical in function- so why would 25% be right? - the cluster answer is right and certainly makes more sense and is easier to setup.
Correct Answers:
- B On the router in each office, configure a DHCP relay
- E On each DHCP scope, configure DHCP failover
https://serverfault.com/questions/710642/symmetric-dhcp-failover-configuration
Correct, see https://docs.microsoft.com/en-us/learn/modules/deploy-manage-dynamic-host-configuration-protocol/7-implement-dynamic-host-configuration-protocol-failover.
No need to install a failover clustering feature.
The topology in the linked example is in one subnet. In the question here, a subnet boundary needs to be crossed, that's why B is also necessary.
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