Get Unlimited Contributor Access to the all ExamTopics Exams!
Take advantage of PDF Files for 1000+ Exams along with community discussions and pass IT Certification Exams Easily.
To determine which of the given IP addresses is a valid host address within the subnet, we need to consider the subnet mask:
172.16.224.255/16
- MASK: 11111111.11111111.|11000000.00000000
- To determine if an IP address is a valid host address, we need to check if the host portion (the last 14 bits) is all zero or all ones.
- HOST: 10101100.0001 0000.11|000000.11111111
- That's a valid host.
255.255.255.255/32
- That's a Broadcast.
224.1.2.1/8
- That range is reserved for multicast address.
192.168.24.59/30
- MASK: 11111111.11111111.11111111.111111|00
- To determine if an IP address is a valid host address, we need to check if the host portion (the last 2 bits) is all zero or all ones.
- HOST: 1100 0000.10101000.00011000.001110|11
- That's a Broadcast.
So, the correct answer is A.
The valid answer is A, because the start Network: 172.16.192.0/18 & Broadcast: 172.16.255.255 everything in between is valid host.
the answer C is wrong because it's multicast address not host address.
thank you,
Answer is C
A) 172.16.224.255/18 -> valid host is range 172.16.192.1 - 172.16.255.254, so 172.16.224.255 is not valid host address. instead it is broadcast address.
B) 255.255.255.255/32 -> obviously not a valid host address
C) 224.1.2.1/8 -> Valid host is range 224.0.0.1 - 224.255.255.254 so it is valid host address
D) 192.168.24.59/30 - Valid host is range 192.168.24.57 - 192.168.24.58. 192.168.24.59/30 is broadcast address.
Hi, your reasoning for discarding A is wrong. The range is correct:172.16.192.1 - 172.16.255.254. However, the IP 172.16.224.255 is not a broadcast address for the subnet 172.16.224.255/18 since it is not the last IP of the subnet (it is 172.16.224.255). It would be the broadcast address if the subnet was something like 172.16.224.0/24, but it's not. The C cannot be a valid host address because that range is reserved for multicast address. Therefore, the only correct answer is A
I don't think "C" is a valid answer.
As we only use subnetting for class A, Class B and Class C IP range.
224.X.X.X is useful for multicasting purpose (Class-D)
A voting comment increases the vote count for the chosen answer by one.
Upvoting a comment with a selected answer will also increase the vote count towards that answer by one.
So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.
half_dream
6 months, 4 weeks agoChidinnaji
2 years, 1 month agooracledeaf
2 years, 3 months agocipikacipiki
2 years, 3 months agoVicGarcia
10 months, 1 week agoShan_M
2 years, 3 months agoYen_C
2 years, 4 months ago