The interesting thing here is the call sb2 from System.out.println() in method foo();
But thats ok because it happened in new StrBldr() context and sb2 is already assigned.
The correct answer is E. "hey oh hi yo ey"
The foo method in the StrBldr class is called within the main method with a StringBuilder argument of "hey". Inside the foo method, it prints s ("hey"), " oh ", and sb2 ("hi "), then returns a new StringBuilder with "ey". After the foo method is called, the returned StringBuilder ("ey") is appended to sbl ("yo "). So, the final output of sbl is "yo ey". Therefore, the output of the program is the concatenation of the print inside the foo method and the print of sbl in the main method, which is "hey oh hi yo ey".
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